Question

If 200 soldiers eat 10 tons of food in 200 days, how much will 20 soldiers eat in 20 days
(a) 1 ton
(b) 10 kg
(c) 100 kg
(d) 50 kg

Answer 1

Hint: We will use the given condition to find the quantity of food eaten by 1 soldier in 1 day by dividing the amount of food by 200 and then again by 200. Then, multiply it by 20 to find the food eaten by 20 soldiers in 1 day and then multiply it by 20 to find the food for 20 days.

Complete step-by-step answer:
We are given that 200 soldiers eat 10 tons of food in 200 days.
We know that ${\text{1ton = 1000kg}}$
Therefore, 200 soldiers eat 10,000kg in 200 days.
We will find the food eaten by the soldier in 200 days by dividing the total food by 200.
$\dfrac{{10,000}}{{200}} = 50kg$
Similarly, we will divide it by 200 to find the food eaten by 1 soldier in 1 day.
$\dfrac{{50}}{{200}} = \dfrac{1}{4}kg$
Now, let us determine the food eaten by 20 soldiers by multiplying the food eaten by 1 soldier in 1 day by 20.
$\dfrac{1}{4}\left( {20} \right) = 5kg$
And now determine the amount of food eaten by 20 soldiers in 20 days by multiplying the above food by 20.
$5\left( {20} \right) = 100kg$
Hence, 20 soldiers will eat 100kg food in 20 days.
Thus, option C is correct.

Note: We can also find the number of food eaten by 1 soldier in 1 day by dividing the total food by $\dfrac{{10,000}}{{200 \times 200}}$ and then multiply this by $20 \times 20$ to find the food eaten by 20 soldiers in 20 days. Also, one must know that there are 1000kg in 1 ton.