Answer
Verified
486.3k+ views
Hint: As we know that the union of the sets means the collection of all the elements present in the two sets and intersection is the collection of those elements which are in common between the sets. We will apply these definitions between the sets which are considered under union and intersection.
Complete step-by-step answer:
Here we will consider the expression (B $\cup $ D) $\cap $ (B $\cup $ C). After looking at the expression we can clearly observe that the sets which are taken under the union operation are B and D , B and C where B = {4, 5, 6, 7, 8}, C = {7, 8, 9, 10, 11} and D = {10, 11, 12, 13, 14}. Now, we will start one by one.
We will first take the expression (B $\cup $ D). Now we will consider the sets B = {4, 5, 6, 7, 8} and D = {10, 11, 12, 13, 14}. Since, we are taking union operations here. So, by the definition of union states the collection of all the elements present in the sets. Therefore, the elements in A and B are 4, 5, 6, 7, 8, 10, 11, 12, 13 and 14. We can write it as,
(B $\cup $ D) = {4, 5, 6, 7, 8} $\cup $ {10, 11, 12, 13, 14}
Therefore, we have (B $\cup $ D) = {4, 5, 6, 7, 8, 10, 11, 12, 13, 14}.
Now we will find the union between the sets for B and C for the expression (B $\cup $ C). For that we have elements B = {4, 5, 6, 7, 8} and C = {7, 8, 9, 10, 11}. And the elements between these are 4, 5, 6, 7, 8, 9, 10 and 11. And, we can write it as,
(B $\cup $ C) = {4, 5, 6, 7, 8} $\cup $ {7, 8, 9, 10, 11}
Therefore, we have (B $\cup $ C) = {4, 5, 6, 7, 8, 9, 10, 11}.
Now we will take the intersection as (B $\cup $ D) $\cap $ (B $\cup $ C). And we will apply the definition of intersection here. That is we will collect common elements. Thus, we have that (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11, 12, 13, 14} $\cap $ {4, 5, 6, 7, 8, 9, 10, 11}. Therefore, we get (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11}.
Hence, (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11}.
Note: As we apply the union operation we are free to collect all the elements that are present between those sets on which the union operation is on. While applying intersection between the sets we consider only those elements which are common between the sets. We must also take care not to repeat any elements in any set, we must represent it only one time.
Complete step-by-step answer:
Here we will consider the expression (B $\cup $ D) $\cap $ (B $\cup $ C). After looking at the expression we can clearly observe that the sets which are taken under the union operation are B and D , B and C where B = {4, 5, 6, 7, 8}, C = {7, 8, 9, 10, 11} and D = {10, 11, 12, 13, 14}. Now, we will start one by one.
We will first take the expression (B $\cup $ D). Now we will consider the sets B = {4, 5, 6, 7, 8} and D = {10, 11, 12, 13, 14}. Since, we are taking union operations here. So, by the definition of union states the collection of all the elements present in the sets. Therefore, the elements in A and B are 4, 5, 6, 7, 8, 10, 11, 12, 13 and 14. We can write it as,
(B $\cup $ D) = {4, 5, 6, 7, 8} $\cup $ {10, 11, 12, 13, 14}
Therefore, we have (B $\cup $ D) = {4, 5, 6, 7, 8, 10, 11, 12, 13, 14}.
Now we will find the union between the sets for B and C for the expression (B $\cup $ C). For that we have elements B = {4, 5, 6, 7, 8} and C = {7, 8, 9, 10, 11}. And the elements between these are 4, 5, 6, 7, 8, 9, 10 and 11. And, we can write it as,
(B $\cup $ C) = {4, 5, 6, 7, 8} $\cup $ {7, 8, 9, 10, 11}
Therefore, we have (B $\cup $ C) = {4, 5, 6, 7, 8, 9, 10, 11}.
Now we will take the intersection as (B $\cup $ D) $\cap $ (B $\cup $ C). And we will apply the definition of intersection here. That is we will collect common elements. Thus, we have that (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11, 12, 13, 14} $\cap $ {4, 5, 6, 7, 8, 9, 10, 11}. Therefore, we get (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11}.
Hence, (B $\cup $ D) $\cap $ (B $\cup $ C) = {4, 5, 6, 7, 8, 10, 11}.
Note: As we apply the union operation we are free to collect all the elements that are present between those sets on which the union operation is on. While applying intersection between the sets we consider only those elements which are common between the sets. We must also take care not to repeat any elements in any set, we must represent it only one time.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
If the coordinates of the points A B and C be 443 23 class 10 maths JEE_Main
If the mean of the set of numbers x1x2xn is bar x then class 10 maths JEE_Main
What is the meaning of celestial class 10 social science CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In the tincture of iodine which is solute and solv class 11 chemistry CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE