
If the measured values of two quantities are $A \pm \Delta A$ and $B \pm \Delta B$, $\Delta A$ and $\Delta B$ being the mean absolute errors. What is the maximum possible error in A+B?
Show that if $Z = \dfrac{A}{B}{\text{ then }}\dfrac{{\Delta Z}}{Z} = \dfrac{{\Delta A}}{A} + \dfrac{{\Delta B}}{B}$.
Answer
470.7k+ views
Hint: Whenever we measure the physical quantity experimentally, we repeat the experiment many times and take many readings to eliminate the errors. Usually errors will be added when we add two physical quantities because we always care about the maximum error one can obtain.
Formula used:
$\ln \left[ {\dfrac{A}{B}} \right] = \ln \left[ A \right] - \ln \left[ B \right]$
$d(\ln z) = \dfrac{{dz}}{z}$
Complete step by step answer:
Usually errors can be broadly classified into two categories. They are systematic errors and random errors. Zero errors and improperly calibrated instrument errors come under systematic errors. Zero errors can be further classified into two types. They are positive zero error and negative zero error. If there is a positive zero error then to the final reading we should subtract the error and if it is a negative zero error then in the final reading we should add the error. By properly calibrating the instrument we can reduce the systematic error.
The proper way of representing the physical quantity measured is a combination of actual value and its error.
We were given with $A \pm \Delta A$ and $B \pm \Delta B$
If we add A and B, then we should add errors too to get the maximum possible error in A+B.
Hence the maximum possible error in A+B will be $\Delta A + \Delta B$
We were given with
$Z = \dfrac{A}{B}{\text{ }}$
By applying logarithm on bo0th sides we will get
$\eqalign{
& \Rightarrow \ln \left[ {\dfrac{A}{B}} \right] = \ln \left[ A \right] - \ln \left[ B \right] \cr
& \therefore \ln \left[ Z \right] = \ln \left[ A \right] - \ln \left[ B \right] \cr} $
$d(\ln z) = \dfrac{{dz}}{z}$
By differentiating of both sides we will get
$ \dfrac{{\Delta Z}}{Z} = \dfrac{{\Delta A}}{A} + \dfrac{{\Delta B}}{B}$
The reason why we added errors is because we always find out the maximum error.
Hence proved.
Note:
The proof for the second statement can also be done without applying logarithm on both sides too. There is the formula to find out the differential of ratio of two quantities. We will get the same answer by that method too. Even in the experiment to determine the time period of the pendulum, we add the errors.
Formula used:
$\ln \left[ {\dfrac{A}{B}} \right] = \ln \left[ A \right] - \ln \left[ B \right]$
$d(\ln z) = \dfrac{{dz}}{z}$
Complete step by step answer:
Usually errors can be broadly classified into two categories. They are systematic errors and random errors. Zero errors and improperly calibrated instrument errors come under systematic errors. Zero errors can be further classified into two types. They are positive zero error and negative zero error. If there is a positive zero error then to the final reading we should subtract the error and if it is a negative zero error then in the final reading we should add the error. By properly calibrating the instrument we can reduce the systematic error.
The proper way of representing the physical quantity measured is a combination of actual value and its error.
We were given with $A \pm \Delta A$ and $B \pm \Delta B$
If we add A and B, then we should add errors too to get the maximum possible error in A+B.
Hence the maximum possible error in A+B will be $\Delta A + \Delta B$
We were given with
$Z = \dfrac{A}{B}{\text{ }}$
By applying logarithm on bo0th sides we will get
$\eqalign{
& \Rightarrow \ln \left[ {\dfrac{A}{B}} \right] = \ln \left[ A \right] - \ln \left[ B \right] \cr
& \therefore \ln \left[ Z \right] = \ln \left[ A \right] - \ln \left[ B \right] \cr} $
$d(\ln z) = \dfrac{{dz}}{z}$
By differentiating of both sides we will get
$ \dfrac{{\Delta Z}}{Z} = \dfrac{{\Delta A}}{A} + \dfrac{{\Delta B}}{B}$
The reason why we added errors is because we always find out the maximum error.
Hence proved.
Note:
The proof for the second statement can also be done without applying logarithm on both sides too. There is the formula to find out the differential of ratio of two quantities. We will get the same answer by that method too. Even in the experiment to determine the time period of the pendulum, we add the errors.
Recently Updated Pages
How do you factor x2 + x 20 0 class 9 maths CBSE

How do you solve y6x and 2x+3y20 using substitutio class 9 maths CBSE

Chipko movement originated in Gopeshwar in A 1953 B class 9 biology CBSE

The adjacent sides in the parallelogram are supplementary class 9 maths CBSE

The compound used in plastic industry is A Vinyl acetate class 9 chemistry CBSE

How do you solve for y in 2left y dfrac12 right 4left class 9 maths CBSE

Trending doubts
According to Bernoullis equation the expression which class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Differentiate between calcination and roasting class 11 chemistry CBSE

A solution of a substance X is used for white washing class 11 chemistry CBSE

What is spore formation class 11 biology CBSE

10 examples of friction in our daily life
