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If the number was exactly divisible by \[5\] from the number \[5\] to \[85\] are arranged in a descending order then which number would appear at the eleventh place from the bottom .
A. \[35\]
B. \[45\]
C. \[50\]
D. \[60\]
E. None of these

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Answer
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Hint: In this question, we need to find the number that would appear at the eleventh place from the bottom from which the numbers \[5\] to \[85\] are arranged in a descending order. First, we need to know the concept of the divisibility rule of \[5\] that is if a number ends in a \[0\] or \[5\] , it is divisible by \[5\] . By using this property, we can find all the numbers divisible by \[5\] from the number \[5\] to \[85\] in descending order. Then we have to find which number is on the eleventh place from the bottom.

Complete step by step solution:
Here we need to find the number that would appear at the eleventh place from the bottom from which the numbers \[5\] to \[85\] are arranged in a descending order.
Divisibility rule of \[5\] :
The divisibility rule of \[5\] is that if a number ends in a \[0\] or \[5\] , it is divisible by \[5\] .
Now let's find all the numbers divisible by \[5\] from the number \[5\] to \[85\] in descending order.
So the numbers are \[85,80,75,70,65,60,55,50,45,40,35,30,25,20,15,10,5\]
Totally there are \[17\] numbers.
Now let us find which number is on the eleventh place from the bottom.
On counting from the bottom,
We get,
The number in the eleventh place from the bottom is \[55\]
So the number in the eleventh place from the bottom is \[55\] which is not in the option.
Thus our answer is none of these.
Final answer :
The number in the eleventh place from the bottom is \[55\] which is not in the option.
Option E) . None of these is the correct answer.

Therefore, the correct option is E

Note: In order to solve these types of questions , we must always keep in mind the divisibility rule of the numbers to find out the results easily. The division rule is nothing but which helps us to check whether the given number is divisible by another number without using the actual method of division. We also need to know that if the number is completely divisible by another number then the quotient will be a whole number and the remainder will be zero.