Question

In a cricket match, the captain of the team played for 4 hours 28 minutes 13 second in the first innings and 3 hours 49 minutes 35 seconds in the second innings. Find out how much more time he played in the first innings.

Answer 1

Hint: In this question we have to find out the difference of time of play in first inning to second inning. So, it is a simple algebraic subtraction. In order to subtract we have to calculate time of play in the same unit. So, we first convert hours to minutes and minutes to seconds. We use following conversion factors
$\begin{align}
  & 1\text{ hour = 60 minutes} \\
 & \text{1 minutes = 60 seconds} \\
\end{align}$
Convert 4 hours 28 minutes 13 seconds in seconds and 3 hours 49 minutes 35 seconds in seconds and then subtract to get the result in seconds. After getting the result converted second into hours, minutes and seconds to get an answer in standard forms.

Complete step-by-step answer:
The captain of team played 4 hours 28 minute 13 seconds
So, we convert the above in seconds
$\begin{align}
  & 4\text{ hours =4(60) minutes} \\
 & \text{4(60) minutes = 4(60)(60)seconds} \\
 & \Rightarrow \text{4 hours = 14400 seconds} \\
\end{align}$
Now we convert 28 minutes in seconds as
$28\text{ minutes = 28(60) seconds}$
So, 28 minutes = 1680 seconds
So, total time the captain played in first inning= 14400+1680+13=16093 seconds
Now in the second inning
The captain of team played 3 hours 49 minute 35 seconds
So, we convert the above in seconds
$\begin{align}
  & \text{3 hours =3(60) minutes} \\
 & \text{3(60) minutes = 3(60)(60)seconds} \\
 & \Rightarrow 3\text{ hours = 10800 seconds} \\
\end{align}$
Now we convert 49 minutes in seconds as
$\text{49 minutes = 49(60) seconds}$
So, 28 minutes = 2940 seconds
So, total time the captain played in second inning$=10800+2940+35=13775\text{ }$seconds
Now the difference of two innings is equal to time of play in first in first inning minus time of play in second inning.
Suppose the more time play is T
So, we can write
$\begin{align}
  & T=16093-13775 \\
 & \Rightarrow T=2318\text{ Seconds } \\
\end{align}$
So, the captain played 2318 second more in the first inning as compared to second, now we cave to convert it in hours, minutes and seconds.
First, we divide 2318 second by 60 so we can write it as
$2318=38(60)+38$
So, we can write
2318 second = 38 minutes 38 seconds.
Hence, we can say that the captain played 0hour 38 minute 38 seconds more time in the first inning as compared to the second innings.


NOTE: Addition and subtraction is defined only when units are the same, that is only two similar things can be added or subtracted. In this question we can convert all units in hours only or in minutes, then we subtract to get the result in the respective units. Finally, we convert the time in standard form that is in hours, minutes, and seconds.