In a series LCR circuit connected to an ac source of variable frequency and voltage $v = {v_m}\sin \omega t$ , draw a plot showing the variation of current $(I)$ with angular frequency $(\omega )$ for two different values of resistance ${R_1}$ and ${R_2}$ $({R_1} > {R_2})$ , Write the condition under which the phenomenon of resonance occurs. For which value of the resistance out of the two curves a sharper resonance is produced? Define Q-factor of the circuit and give its significance.
Answer
Verified
115.8k+ views
Hint: In order to solve this question one should be aware of the concept of resonance and the conditions of resonance in an LCR circuit. The condition of the resonance depends on a particular frequency, also known as resonance frequency. When the frequency of the LCR is equal to the resonance frequency only then the condition of resonance is attained.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Complete step by step solution:
The condition for resonance in the LCR circuit is given by,
${\omega _o} = \dfrac{1}{{\sqrt {LC} }}$
Here, we can easily observe that the amplitude of the current is maximum at the resonance frequency ${\omega _o}$ . Since, ${i_m} = {V_m}IR$ at resonance, the amplitude of current for case ${R_2}$ is sharper to that for case ${R_1}$ . The quality factor or can be said as the Q-factor of a resonance LCR circuit is defined as the ratio of voltage drop across the capacitor to that of applied voltage.
It is given by,
$Q = \dfrac{1}{R}\sqrt {\dfrac{L}{C}} $
The Q-factor or Quality factor determines the sharpness of the resonance curve. If the resonance curve is less sharp, then the maximum current decreases and also the circuit is close to the resonance for a larger range $\Delta \omega $ of frequencies and the regulation of the circuit then will not be good. Therefore, the sharp resonance curve is better.
Note: Less sharp the resonance is better, as for less sharp resonance curve, less is the selectivity of the circuit while the Q-Factor will be higher, sharper is the resonance curve and lesser will be the loss in energy of the circuit.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation
How to find Oxidation Number - Important Concepts for JEE
How Electromagnetic Waves are Formed - Important Concepts for JEE
Electrical Resistance - Important Concepts and Tips for JEE
Average Atomic Mass - Important Concepts and Tips for JEE
Chemical Equation - Important Concepts and Tips for JEE
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
JEE Main Login 2045: Step-by-Step Instructions and Details
Physics Average Value and RMS Value JEE Main 2025
Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs
Dual Nature of Radiation and Matter Class 12 Notes CBSE Physics Chapter 11 (Free PDF Download)
Inductive Effect and Acidic Strength - Types, Relation and Applications for JEE
Degree of Dissociation and Its Formula With Solved Example for JEE
Diffraction of Light - Young’s Single Slit Experiment
JEE Main 2025: Derivation of Equation of Trajectory in Physics