Answer
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Hint: From the figure, circles are touching each other from outside. We can prove the required statement using the concept of tangent and a point lies outside the circle.
Complete step-by-step answer:
Here we are given that two circles touch each other at point C
Since, we know that lengths of tangent drawn from an external point to a circle are equal.
So consider circle with centre A
According to external point theorem
RP=RC
Similarly consider circle with centre B
RQ=RC
$\therefore RP = RC$ and $RC = RQ$
$ \to RP = RQ$
Hence we can say that R is the mid-point of P and Q
Hence the common tangent to the circles at C, bisects the common tangent at P and Q.
Note: Circles can touch each other internally and externally but the concept of tangent has been used and tangent cannot pass through the inside circle. Definition of tangent is given as a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.
Complete step-by-step answer:
Here we are given that two circles touch each other at point C
Since, we know that lengths of tangent drawn from an external point to a circle are equal.
So consider circle with centre A
According to external point theorem
RP=RC
Similarly consider circle with centre B
RQ=RC
$\therefore RP = RC$ and $RC = RQ$
$ \to RP = RQ$
Hence we can say that R is the mid-point of P and Q
Hence the common tangent to the circles at C, bisects the common tangent at P and Q.
Note: Circles can touch each other internally and externally but the concept of tangent has been used and tangent cannot pass through the inside circle. Definition of tangent is given as a straight line or plane that touches a curve or curved surface at a point, but if extended does not cross it at that point.
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