
In how many ways 7 pictures can be hung from 5 picture nails on a wall?
Answer
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Hint: In this question we have to find the number of ways to hang 7 pictures from 5 picture nails on a wall, it means we have to choose 5 nails at a time. To solve this question we will use the concept of permutation. The basic permutation formula is given as
${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$
Where, n is the total number of objects and r is the number of choices.
Complete step by step solution:
We have to find the number of ways to hang 7 pictures from 5 picture nails on a wall.
Now, we know that a permutation is the arrangement of a set of data in some specific order. If we have total number of n datasets and we have to choose r objects from the dataset then the basic permutation formula is given as:
${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$
Where, n is the total number of objects and r is the number of choices.
Here we have a total 7 numbers of objects and we have to choose 5 at a time.
So the total number of ways to choose 5 out of 7 pictures will be
$\Rightarrow {}^{7}{{P}_{5}}=\dfrac{7!}{\left( 7-5 \right)!}$
Now, simplifying the above obtained equation we will get
$\begin{align}
& \Rightarrow {}^{7}{{P}_{5}}=\dfrac{7\times 6\times 5\times 4\times 3\times 2!}{2!} \\
& \Rightarrow {}^{7}{{P}_{5}}=7\times 6\times 5\times 4\times 3 \\
& \Rightarrow {}^{7}{{P}_{5}}=2520 \\
\end{align}$
Hence we get 2520 ways to hang 7 pictures from 5 picture nails on a wall.
Note: Here in this question we can also use the concept of combination. First we will find the number of ways of selecting the 5 pictures out of and then find the number of ways to arrange 5 pictures on the 5 picture nails. Then multiplying both will give the desired answer.
Now, number of ways to select 5 pictures out of 7 will be
\[\begin{align}
& \Rightarrow {}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!} \\
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7!}{5!\left( 7-5 \right)!} \\
\end{align}\]
Now, simplifying the above obtained equation we will get
$\begin{align}
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7\times 6\times 5!}{5!\times 2!} \\
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7\times 6}{2\times 1} \\
& \Rightarrow {}^{7}{{C}_{5}}=21 \\
\end{align}$
So there are a total 21 ways of selecting 5 pictures.
Now, total number of ways in which 5 pictures can be arranged on 5 picture nails will be $5!$
Now, the number of ways to hang 7 pictures from 5 picture nails on a wall will be
$\begin{align}
& \Rightarrow 21\times 5\times 4\times 3\times 2\times 1 \\
& \Rightarrow 2520 \\
\end{align}$
Hence above is the required answer.
${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$
Where, n is the total number of objects and r is the number of choices.
Complete step by step solution:
We have to find the number of ways to hang 7 pictures from 5 picture nails on a wall.
Now, we know that a permutation is the arrangement of a set of data in some specific order. If we have total number of n datasets and we have to choose r objects from the dataset then the basic permutation formula is given as:
${}^{n}{{P}_{r}}=\dfrac{n!}{\left( n-r \right)!}$
Where, n is the total number of objects and r is the number of choices.
Here we have a total 7 numbers of objects and we have to choose 5 at a time.
So the total number of ways to choose 5 out of 7 pictures will be
$\Rightarrow {}^{7}{{P}_{5}}=\dfrac{7!}{\left( 7-5 \right)!}$
Now, simplifying the above obtained equation we will get
$\begin{align}
& \Rightarrow {}^{7}{{P}_{5}}=\dfrac{7\times 6\times 5\times 4\times 3\times 2!}{2!} \\
& \Rightarrow {}^{7}{{P}_{5}}=7\times 6\times 5\times 4\times 3 \\
& \Rightarrow {}^{7}{{P}_{5}}=2520 \\
\end{align}$
Hence we get 2520 ways to hang 7 pictures from 5 picture nails on a wall.
Note: Here in this question we can also use the concept of combination. First we will find the number of ways of selecting the 5 pictures out of and then find the number of ways to arrange 5 pictures on the 5 picture nails. Then multiplying both will give the desired answer.
Now, number of ways to select 5 pictures out of 7 will be
\[\begin{align}
& \Rightarrow {}^{n}{{C}_{r}}=\dfrac{n!}{r!\left( n-r \right)!} \\
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7!}{5!\left( 7-5 \right)!} \\
\end{align}\]
Now, simplifying the above obtained equation we will get
$\begin{align}
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7\times 6\times 5!}{5!\times 2!} \\
& \Rightarrow {}^{7}{{C}_{5}}=\dfrac{7\times 6}{2\times 1} \\
& \Rightarrow {}^{7}{{C}_{5}}=21 \\
\end{align}$
So there are a total 21 ways of selecting 5 pictures.
Now, total number of ways in which 5 pictures can be arranged on 5 picture nails will be $5!$
Now, the number of ways to hang 7 pictures from 5 picture nails on a wall will be
$\begin{align}
& \Rightarrow 21\times 5\times 4\times 3\times 2\times 1 \\
& \Rightarrow 2520 \\
\end{align}$
Hence above is the required answer.
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