Answer
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Hint: In the charged state, the chemical energy of the battery is stored in the potential difference between the pure lead at the negative side and the $Pb{O_2}$ on the positive side, plus the aqueous sulfuric acid. The electrical energy produced by a discharging lead–acid battery can be attributed to the energy released when the strong chemical bonds of water $({H_2}O)$ molecules are formed from ${H^ + }$ ions of the acid and ${O^ - }_2$ ions of $Pb{O_2}$ . Conversely, during charging, the battery acts as a water-splitting device.
Complete Step by step answer: Step 1: Firstly, we must enlist all the components of the Lead Storage Battery, the material in a cell which takes active participation in a chemical reaction (absorption or evolution of electrical energy) during charging or discharging is called the active material of the cell. The active elements of the lead acid are
Lead peroxide $(Pb{O_2})$ – It forms the positive active material. The $Pb{O_2}$ are dark chocolate brooms in colour.
Sponge lead – Its form the negative active material. It is grey in colour.
Dilute Sulfuric Acid $({H_2}S{O_4})$ – It is used as an electrolyte. It contains 31% of sulfuric acid.
Step 2: From the components we can conclude the correct option/options. Since the Active material i.e. Lead forms a negative part that is anode, so the first option is correct. And the positive active material is $Pb{O_2}$ , so the second option is also correct. And the electrolyte which is used in this is ${H_2}S{O_4}$ , so the third option is also correct.
Hence we can say that option D (all are correct) is the correct option.
Note: Lead-acid batteries can be classified as secondary batteries. The chemical reactions that occur in secondary cells are reversible. The reactants that generate an electric current in these batteries (via chemical reactions) can be regenerated by passing current through the battery (recharging).
Complete Step by step answer: Step 1: Firstly, we must enlist all the components of the Lead Storage Battery, the material in a cell which takes active participation in a chemical reaction (absorption or evolution of electrical energy) during charging or discharging is called the active material of the cell. The active elements of the lead acid are
Lead peroxide $(Pb{O_2})$ – It forms the positive active material. The $Pb{O_2}$ are dark chocolate brooms in colour.
Sponge lead – Its form the negative active material. It is grey in colour.
Dilute Sulfuric Acid $({H_2}S{O_4})$ – It is used as an electrolyte. It contains 31% of sulfuric acid.
Step 2: From the components we can conclude the correct option/options. Since the Active material i.e. Lead forms a negative part that is anode, so the first option is correct. And the positive active material is $Pb{O_2}$ , so the second option is also correct. And the electrolyte which is used in this is ${H_2}S{O_4}$ , so the third option is also correct.
Hence we can say that option D (all are correct) is the correct option.
Note: Lead-acid batteries can be classified as secondary batteries. The chemical reactions that occur in secondary cells are reversible. The reactants that generate an electric current in these batteries (via chemical reactions) can be regenerated by passing current through the battery (recharging).
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