Answer
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Hint: Consider a convex mirror. Take an object in front of the mirror and describe the direction of light rays after reflection from the mirror to get the intersecting points to get the image. Magnification is measured in terms of the height of the object and the image formed. Compare the heights to get your answer.
Complete step-by-step answer:
Convex mirror is a spherical mirror where the reflective surface is outside the curved area. Convex mirror always diverges the light outward. It will not focus the light anywhere.
In the above diagram image formation is shown in a convex mirror.
Here, C is the centre of the sphere the mirror is a part of called the centre of curvature, F is the focal length of the mirror. The light rays from the object will reflect at the surface of the convex mirror and diverge outwards. The diverged ray seemed to come out of the mirror from the focal point. The ray through the centre of curvature will reflect and diverge in the opposite direction. This ray seems to come out of the centre of curvature of the mirror. Both imaginary rays will intersect at point and we will get the image.
Since, both the focal point and the centre of curvature are imaginary the image formed will be always virtual. This virtual image is always diminished. As the object will get closer to the mirror the image will get bigger and bigger but it will not get bigger than the original object.
So, the image formed in a convex mirror is always virtual and diminished. So, the magnification of a convex mirror is always less than 1.
The correct option is (B).
Note: In case of a convex mirror the magnification of the image formed is always less than 1. But if we consider a concave mirror depending on the position of the object magnification may be less than 1 or equal to 1 or greater than 1.
Complete step-by-step answer:
Convex mirror is a spherical mirror where the reflective surface is outside the curved area. Convex mirror always diverges the light outward. It will not focus the light anywhere.
In the above diagram image formation is shown in a convex mirror.
Here, C is the centre of the sphere the mirror is a part of called the centre of curvature, F is the focal length of the mirror. The light rays from the object will reflect at the surface of the convex mirror and diverge outwards. The diverged ray seemed to come out of the mirror from the focal point. The ray through the centre of curvature will reflect and diverge in the opposite direction. This ray seems to come out of the centre of curvature of the mirror. Both imaginary rays will intersect at point and we will get the image.
Since, both the focal point and the centre of curvature are imaginary the image formed will be always virtual. This virtual image is always diminished. As the object will get closer to the mirror the image will get bigger and bigger but it will not get bigger than the original object.
So, the image formed in a convex mirror is always virtual and diminished. So, the magnification of a convex mirror is always less than 1.
The correct option is (B).
Note: In case of a convex mirror the magnification of the image formed is always less than 1. But if we consider a concave mirror depending on the position of the object magnification may be less than 1 or equal to 1 or greater than 1.
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