
What is the maximum flow speed of water for laminar flow in a pipe having a diameter \[5cm\] given that coefficient of viscosity of water is \[{10^{ - 3}}Pa\sec .\]
Answer
128.1k+ views
Hint:To solve this problem,we will apply Reynold's number formula for the laminar flow. Reynold’s number is dimensionless number as it is the ratio of Inertial force to viscous force. Reynold’s number is denoted by \[{N_{\operatorname{Re} }}\]. Mathematically, the Reynold’s number is calculated as,
\[{N_{\operatorname{Re} }} = \dfrac{{\rho vd}}{\mu }\] ……(1)
Where, \[{N_{\operatorname{Re} }}\] is Reynolds’s number and its numerical value for the laminar flow is 2000.
\[\rho \] Is the density of the fluid
\[v\] is the average flow speed or average velocity of the flow
\[d\] is the diameter of the pipe
\[\mu \] is the coefficient of viscosity or dynamic viscosity
Complete step by step solution:
Given that:
Diameter of the pipe is, \[d = 5cm\]
The coefficient of viscosity is, \[\mu = {10^{ - 3}}Pa\sec .\]
The density of water is, \[\rho = 1000\dfrac{{kg}}{{m{}^3}}\]
Now put all the given values in equation (1)
${N_{\operatorname{Re} }} = \dfrac{{\rho vd}}{\mu } \\
v = \dfrac{{{N_{\operatorname{Re} }}\mu }}{{\rho d}} \\
v = \dfrac{{2000 \times {{10}^{ - 3}}}}{{1000 \times 0.05}} \\
v = 4\dfrac{{\text{m}}}{{\text{s}}} \\
$
As we know, for laminar flow the maximum flow speed is twice the average flow speed.
Thus the maximum flow speed of water for laminar flow in a pipe is calculated as,
\[
{v_{\max }} = 2 \times v \\
= 2 \times 4 \\
= 8\dfrac{{\text{m}}}{{\text{s}}} \\
\]
Therefore, the maximum flow speed of water for laminar flow in a pipe is \[{v_{\max }} = 8\dfrac{{\text{m}}}{{\text{s}}}\].
Note: Laminar flow is also known as stream line flow because the fluid particles travel in a regular, smooth and in straight line path. On the other side, if the fluid particles travel in irregular or zig-zag ways then the flow is known as turbulent flow.
If the value of Reynolds’s number is equal to or less than 2000 then the flow is considered as laminar flow. If the value of Reynolds’s number is more than 4000 then the flow is considered as turbulent flow.
\[{N_{\operatorname{Re} }} = \dfrac{{\rho vd}}{\mu }\] ……(1)
Where, \[{N_{\operatorname{Re} }}\] is Reynolds’s number and its numerical value for the laminar flow is 2000.
\[\rho \] Is the density of the fluid
\[v\] is the average flow speed or average velocity of the flow
\[d\] is the diameter of the pipe
\[\mu \] is the coefficient of viscosity or dynamic viscosity
Complete step by step solution:
Given that:
Diameter of the pipe is, \[d = 5cm\]
The coefficient of viscosity is, \[\mu = {10^{ - 3}}Pa\sec .\]
The density of water is, \[\rho = 1000\dfrac{{kg}}{{m{}^3}}\]
Now put all the given values in equation (1)
${N_{\operatorname{Re} }} = \dfrac{{\rho vd}}{\mu } \\
v = \dfrac{{{N_{\operatorname{Re} }}\mu }}{{\rho d}} \\
v = \dfrac{{2000 \times {{10}^{ - 3}}}}{{1000 \times 0.05}} \\
v = 4\dfrac{{\text{m}}}{{\text{s}}} \\
$
As we know, for laminar flow the maximum flow speed is twice the average flow speed.
Thus the maximum flow speed of water for laminar flow in a pipe is calculated as,
\[
{v_{\max }} = 2 \times v \\
= 2 \times 4 \\
= 8\dfrac{{\text{m}}}{{\text{s}}} \\
\]
Therefore, the maximum flow speed of water for laminar flow in a pipe is \[{v_{\max }} = 8\dfrac{{\text{m}}}{{\text{s}}}\].
Note: Laminar flow is also known as stream line flow because the fluid particles travel in a regular, smooth and in straight line path. On the other side, if the fluid particles travel in irregular or zig-zag ways then the flow is known as turbulent flow.
If the value of Reynolds’s number is equal to or less than 2000 then the flow is considered as laminar flow. If the value of Reynolds’s number is more than 4000 then the flow is considered as turbulent flow.
Recently Updated Pages
Difference Between Vapor and Gas: JEE Main 2024

Area of an Octagon Formula - Explanation, and FAQs

Difference Between Solute and Solvent: JEE Main 2024

Absolute Pressure Formula - Explanation, and FAQs

Carbon Dioxide Formula - Definition, Uses and FAQs

Charle's Law Formula - Definition, Derivation and Solved Examples

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Login 2045: Step-by-Step Instructions and Details

Class 11 JEE Main Physics Mock Test 2025

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

JEE Mains 2025 Correction Window Date (Out) – Check Procedure and Fees Here!

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement
