Answer
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Hint: The formula of methylamine is $C{H_3}N{H_2}$, it is an organic compound. It is the derivative of ammonia in which the methyl group replaces the hydrogen atom. It is a very important organic compound for the synthesis of the different commercial products.
Complete step by step answer:
The preparation of the methylamine takes place as follows:
$N{H_3} + C{H_3}OH \to C{H_3}N{H_2} + {H_2}O$
Ammonia reacts with methanol or ethyl alcohol to form the methylamine and water as the by product in the reaction. The structure of methylamine is given below:
Therefore when methylamine ($C{H_3}N{H_2}$) reacts with sodium hydroxide ($NaOH$) Methylamine ($C{H_3}N{H_2}$), sodium chloride ($NaCl$) and water (${H_2}O$) are formed in the reaction. Thus option D is the correct answer
$C{H_3}N{H_3}^ + C{l^ - } + NaOH \to C{H_3}N{H_2} + NaCl + {H_2}O$
In the above reaction, dimethylamine and trimethylamine are also formed along with the methylamine but the amount of the reactants taken i.e; their ratio, reaction kinetics determines the most favoured product during the reaction.
Another product formed during the reaction is sodium chloride and the chemical name of the compound is known as the common salt which is used by us in our day to day life and it is an electrolyte which has many biological roles in our body it maintains the amount of water and salts balance in our body and also plays a vital role in the nerve impulse conduction.
But the overdose of this compound can lead to vomiting, stomach cramps, uneven heart rate, and weakness, swelling in the hands or feet. The feeling of restlessness is also a symptom.
So therefore option D is the correct answer.
Note:
Methylamine is an unhindered amine and thus it acts as a good nucleophile. It is considered as a weak base it is exclusively used for the preparation of methyl isocyanide as a reactant with the phosgene gas since its properties are analogous to ammonia.
Complete step by step answer:
The preparation of the methylamine takes place as follows:
$N{H_3} + C{H_3}OH \to C{H_3}N{H_2} + {H_2}O$
Ammonia reacts with methanol or ethyl alcohol to form the methylamine and water as the by product in the reaction. The structure of methylamine is given below:
Therefore when methylamine ($C{H_3}N{H_2}$) reacts with sodium hydroxide ($NaOH$) Methylamine ($C{H_3}N{H_2}$), sodium chloride ($NaCl$) and water (${H_2}O$) are formed in the reaction. Thus option D is the correct answer
$C{H_3}N{H_3}^ + C{l^ - } + NaOH \to C{H_3}N{H_2} + NaCl + {H_2}O$
In the above reaction, dimethylamine and trimethylamine are also formed along with the methylamine but the amount of the reactants taken i.e; their ratio, reaction kinetics determines the most favoured product during the reaction.
Another product formed during the reaction is sodium chloride and the chemical name of the compound is known as the common salt which is used by us in our day to day life and it is an electrolyte which has many biological roles in our body it maintains the amount of water and salts balance in our body and also plays a vital role in the nerve impulse conduction.
But the overdose of this compound can lead to vomiting, stomach cramps, uneven heart rate, and weakness, swelling in the hands or feet. The feeling of restlessness is also a symptom.
So therefore option D is the correct answer.
Note:
Methylamine is an unhindered amine and thus it acts as a good nucleophile. It is considered as a weak base it is exclusively used for the preparation of methyl isocyanide as a reactant with the phosgene gas since its properties are analogous to ammonia.
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