Answer
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Hint: We know that when energy is given to the atomic hydrogen, an electron in its ground state excited jumps into higher energy level shells but after a few times it returns to the ground state and emits energy or photons which have different types of wavelength. The emission spectrum of atomic hydrogen is known as hydrogen spectral series which has been divided into a number of spectral series with wavelength.
Complete answer:
This series is classified by the wavelength. The name of the series are following:
Lyman series, Balmer series, Paschen series, Brackett series, Pfund series, Humphrys series etc.
The energy difference between levels in the hydrogen atom shells and the wavelength of the emitted or absorbed energy is given by Rydberg formula:
$\dfrac{1}{\lambda } = {Z^2}{R_\infty }\left( {\dfrac{1}{{{n_1}^2}} - \dfrac{1}{{{n_2}^2}}} \right)$ , where ${n_1}$ is the principal quantum number of lower energy level, ${n_2}$ is the principal quantum number of upper energy level, $Z$ is the atomic number and $R\infty $ is the Rydberg constant.
Lyman series include the emission lines of the electron from an outer orbit of $n\rangle 1$ to the ground state. All the wavelengths in this series are in the ultraviolet region.
The Balmer series includes lines when the electron jumps from the higher energy level to the $n = 2$. Balmer series have the range of visible spectrum of light.
Paschen series lines lie in the infrared region. This series overlaps the brackett series. This series is formed when the electrons have transitioned from the higher level to the $n = 3$.
The similar pattern follows by all the subsequent series. So, for the given question the answer is: Lyman spectral series of hydrogen lies in the ultraviolet region of the electromagnetic spectrum.
Note:
All the spectral series of the hydrogen emission spectrum have their limits of wavelength and lie in the specific region of the electromagnetic spectrum. Only the Balmer series lies in the visible region.
Complete answer:
This series is classified by the wavelength. The name of the series are following:
Lyman series, Balmer series, Paschen series, Brackett series, Pfund series, Humphrys series etc.
The energy difference between levels in the hydrogen atom shells and the wavelength of the emitted or absorbed energy is given by Rydberg formula:
$\dfrac{1}{\lambda } = {Z^2}{R_\infty }\left( {\dfrac{1}{{{n_1}^2}} - \dfrac{1}{{{n_2}^2}}} \right)$ , where ${n_1}$ is the principal quantum number of lower energy level, ${n_2}$ is the principal quantum number of upper energy level, $Z$ is the atomic number and $R\infty $ is the Rydberg constant.
Lyman series include the emission lines of the electron from an outer orbit of $n\rangle 1$ to the ground state. All the wavelengths in this series are in the ultraviolet region.
The Balmer series includes lines when the electron jumps from the higher energy level to the $n = 2$. Balmer series have the range of visible spectrum of light.
Paschen series lines lie in the infrared region. This series overlaps the brackett series. This series is formed when the electrons have transitioned from the higher level to the $n = 3$.
The similar pattern follows by all the subsequent series. So, for the given question the answer is: Lyman spectral series of hydrogen lies in the ultraviolet region of the electromagnetic spectrum.
Note:
All the spectral series of the hydrogen emission spectrum have their limits of wavelength and lie in the specific region of the electromagnetic spectrum. Only the Balmer series lies in the visible region.
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