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Hint:In order to know what will be the product formed when Nitrobenzene is reduced using Sn/HCl, we must first know what a reduction process is. Reduction is a chemical process which involves gain of the electron which will involve decrease in the oxidation number of the compound.
Complete step-by-step answer:Let us first understand what a reduction process is. Reduction is a chemical process which involves gain of the electron which will involve decrease in the oxidation number of the compound. In other words, we can say loss of the oxygen atom from the molecule and the gain of the hydrogen atom. Let us now move onto the question given. In this nitrobenzene will be reacting with the tin and the hydrochloric acid to give some product. Tin and Hydrochloric acid is a good reducing agent, it will remove the oxygen atom in the Nitrobenzene and will add the hydrogen atom to form the Aniline molecule. The reaction for the reduction of the Nitrobenzene is given below:
Note:There are also other reducing agents which can involve in the reduction process such as
- Lithium Aluminium hydride
- Boron hydride
- Sodium borohydride
- Nascent hydrogen
- Zinc amalgam
- potassium iodide
- Hydrogen peroxide
- Hydrazine
Complete step-by-step answer:Let us first understand what a reduction process is. Reduction is a chemical process which involves gain of the electron which will involve decrease in the oxidation number of the compound. In other words, we can say loss of the oxygen atom from the molecule and the gain of the hydrogen atom. Let us now move onto the question given. In this nitrobenzene will be reacting with the tin and the hydrochloric acid to give some product. Tin and Hydrochloric acid is a good reducing agent, it will remove the oxygen atom in the Nitrobenzene and will add the hydrogen atom to form the Aniline molecule. The reaction for the reduction of the Nitrobenzene is given below:
Note:There are also other reducing agents which can involve in the reduction process such as
- Lithium Aluminium hydride
- Boron hydride
- Sodium borohydride
- Nascent hydrogen
- Zinc amalgam
- potassium iodide
- Hydrogen peroxide
- Hydrazine
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