Answer
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Hint: We have to know that alcohols are organic compounds that show hydroxyl groups present in them. We have to know that alcohols could be oxidized to carboxylic acids and aldehydes in the presence of oxidizing agents. We have to know that aldehydes and ketones could be reduced to primary alcohols and secondary alcohols respectively.
Complete answer:
1.Let us see the oxidation of primary alcohols to carboxylic acid
We can obtain carboxylic acid from oxidation of primary alcohols in the presence of strong oxidizing agents like acidified potassium permanganate. We can write the general equation is,
$R - OH\xrightarrow{{{K_2}C{r_2}{O_7}}}R - COOH$
We can use acidified potassium permanganate as a reagent for the oxidation of primary alcohol to carboxylic acid.
2.Let us see the oxidation of primary alcohol to aldehyde.
We can obtain aldehyde from oxidation of primary alcohols in the presence of mild oxidizing agents like pyridinium chlorochromate. We can write the general equation is,
$R - OH\xrightarrow[{C{H_2}C{l_2}}]{{PCC}}R - CHO$
We can use pyridinium chlorochromate in $C{H_2}C{l_2}$ as a reagent for the oxidation of primary alcohol to aldehyde.
3.Let us see the bromination of phenol to 2,4,6-tribromophenol.
We can obtain 2,4,6-tribromophenol by the bromination of phenol in aqueous bromine (or) bromine water. We can equation as,
.
We can use aqueous bromine (or) bromine water as a reagent in the bromination of phenol to 2,4,6-tribromophenol.
4.Let us see now the conversion of benzyl alcohol to benzoic acid.
We can convert benzyl alcohol to benzoic acid using acidified $KMn{O_4}$ (or) alkaline $KMn{O_4}$. This is followed by hydrolysis with dilute sulfuric acid. We can write the chemical equation as,
We can use acidified $KMn{O_4}$ (or) alkaline $KMn{O_4}$. This is followed by hydrolysis with dilute sulfuric acid as a reagent in the conversion of benzyl alcohol to benzoic acid.
5.Let us now see the dehydration reaction of propan-2-ol to propene.
We can use 85% phosphoric acid as a reagent for the dehydration reaction of propan-2-ol to propene. We can write the chemical equation as,
6.Let us now see the conversion of Butan-2-one to butan-2-ol. We know that butan-2-one is a ketone and butan-2-ol is a secondary alcohol. Ketone to secondary alcohol is a reduction reaction. The reduction reaction happens in the presence of reducing agents like sodium borohydride and Lithium aluminum hydride. We can write the chemical equation is,
We can use sodium borohydride (or) lithium aluminum hydride as a reagent for the conversion of 2-butanone to 2-butanol.
Note:
We have to remember that stronger oxidizing agents convert primary alcohol to carboxylic acids directly. Milder oxidizing agents convert secondary alcohols to ketones and primary alcohols to aldehydes. Tertiary alcohols do not undergo any oxidation reaction with alcohols.
Complete answer:
1.Let us see the oxidation of primary alcohols to carboxylic acid
We can obtain carboxylic acid from oxidation of primary alcohols in the presence of strong oxidizing agents like acidified potassium permanganate. We can write the general equation is,
$R - OH\xrightarrow{{{K_2}C{r_2}{O_7}}}R - COOH$
We can use acidified potassium permanganate as a reagent for the oxidation of primary alcohol to carboxylic acid.
2.Let us see the oxidation of primary alcohol to aldehyde.
We can obtain aldehyde from oxidation of primary alcohols in the presence of mild oxidizing agents like pyridinium chlorochromate. We can write the general equation is,
$R - OH\xrightarrow[{C{H_2}C{l_2}}]{{PCC}}R - CHO$
We can use pyridinium chlorochromate in $C{H_2}C{l_2}$ as a reagent for the oxidation of primary alcohol to aldehyde.
3.Let us see the bromination of phenol to 2,4,6-tribromophenol.
We can obtain 2,4,6-tribromophenol by the bromination of phenol in aqueous bromine (or) bromine water. We can equation as,
We can use aqueous bromine (or) bromine water as a reagent in the bromination of phenol to 2,4,6-tribromophenol.
4.Let us see now the conversion of benzyl alcohol to benzoic acid.
We can convert benzyl alcohol to benzoic acid using acidified $KMn{O_4}$ (or) alkaline $KMn{O_4}$. This is followed by hydrolysis with dilute sulfuric acid. We can write the chemical equation as,
We can use acidified $KMn{O_4}$ (or) alkaline $KMn{O_4}$. This is followed by hydrolysis with dilute sulfuric acid as a reagent in the conversion of benzyl alcohol to benzoic acid.
5.Let us now see the dehydration reaction of propan-2-ol to propene.
We can use 85% phosphoric acid as a reagent for the dehydration reaction of propan-2-ol to propene. We can write the chemical equation as,
6.Let us now see the conversion of Butan-2-one to butan-2-ol. We know that butan-2-one is a ketone and butan-2-ol is a secondary alcohol. Ketone to secondary alcohol is a reduction reaction. The reduction reaction happens in the presence of reducing agents like sodium borohydride and Lithium aluminum hydride. We can write the chemical equation is,
We can use sodium borohydride (or) lithium aluminum hydride as a reagent for the conversion of 2-butanone to 2-butanol.
Note:
We have to remember that stronger oxidizing agents convert primary alcohol to carboxylic acids directly. Milder oxidizing agents convert secondary alcohols to ketones and primary alcohols to aldehydes. Tertiary alcohols do not undergo any oxidation reaction with alcohols.
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