Answer
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Hint: Identify the number of chiral carbons to find how many stereoisomers exist. An arbitrary number (n) of chiral centres in a molecule there are as many as ${2^n}$ possible stereoisomers.
Complete step by step answer:
Let’s find the number of chiral carbons in glucose by drawing its structure.
Glucose has four chiral carbons in its aldehyde form, and so there are ${2^4}$ or 16 possible stereoisomers of this formula. These 16 isomers are:
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
Therefore, we can conclude that the correct answer to this question is option B.
Note:
The 16 stereoisomers of glucose along with their D and L forms. The isomers with their C-5 hydroxyl group on the right are called D-, the isomers with C-5 on the left are L-isomers. Each aldohexose is the diastereomer of the other 14 isomers.
Complete step by step answer:
Let’s find the number of chiral carbons in glucose by drawing its structure.
Glucose has four chiral carbons in its aldehyde form, and so there are ${2^4}$ or 16 possible stereoisomers of this formula. These 16 isomers are:
1.
11.
16.
Therefore, we can conclude that the correct answer to this question is option B.
Note:
The 16 stereoisomers of glucose along with their D and L forms. The isomers with their C-5 hydroxyl group on the right are called D-, the isomers with C-5 on the left are L-isomers. Each aldohexose is the diastereomer of the other 14 isomers.
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