
No. of optical isomers of glucose is:
A.8
B.16
C.32
D.4
Answer
494.7k+ views
Hint: Identify the number of chiral carbons to find how many stereoisomers exist. An arbitrary number (n) of chiral centres in a molecule there are as many as possible stereoisomers.
Complete step by step answer:
Let’s find the number of chiral carbons in glucose by drawing its structure.
Glucose has four chiral carbons in its aldehyde form, and so there are or 16 possible stereoisomers of this formula. These 16 isomers are:
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
13.
14.
15.
16.
Therefore, we can conclude that the correct answer to this question is option B.
Note:
The 16 stereoisomers of glucose along with their D and L forms. The isomers with their C-5 hydroxyl group on the right are called D-, the isomers with C-5 on the left are L-isomers. Each aldohexose is the diastereomer of the other 14 isomers.
Complete step by step answer:
Let’s find the number of chiral carbons in glucose by drawing its structure.

Glucose has four chiral carbons in its aldehyde form, and so there are
1.










11.





16.

Therefore, we can conclude that the correct answer to this question is option B.
Note:
The 16 stereoisomers of glucose along with their D and L forms. The isomers with their C-5 hydroxyl group on the right are called D-, the isomers with C-5 on the left are L-isomers. Each aldohexose is the diastereomer of the other 14 isomers.
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