Answer
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Hint: When an object is set beyond the centre of curvature, then a parallel light ray to the principal axis, moves through the focus F. Simultaneously, the other ray passes through the optical centre C and goes undeviating. In this way, a diminished, real and inverted image is formed on the other side of the lens between the focus F and centre of curvature $2F$.
Complete step by step answer:
If we take the object near the lens in the convex lens, the image size keeps on increasing. As we make the object closer to the lens, we get the image enlarged. So, we can tell that the images created can be of different types. We can have diminished inverted images, small sizes inverted images, enlarged inverted images, enlarged erect images. So, in a convex lens, there is a possibility of getting an actual and inverted image.
Image creation in a convex lens can be described with the help of three principal rays.
$1$. The parallel rays to the principal axis move through the focal point after refraction by the lens.
$2$. The ray moving through the optical centre passes directly through the lens and continues without deviation.
$3$. The ray travels through the focal point and becomes parallel to the principal axis.
When an object is positioned beyond the centre of curvature $2F$, then a light ray AO which is parallel to the principal axis, moves through the focus F along the direction OF resulting refraction. Another ray of light AC crosses through the optical centre C and goes direct without any deviation. The two refracted rays meet each other at location A’, between the focus F and centre of curvature $2F$ on the different side of the lens. In this approach, a diminished, inverted, and real image A’B’ is formed.
So, the correct answer is “Option 1”.
Note: When an object is situated in between focus and pole, a virtual image is made. The size of the image is more significant than that of an object. When an object is set at the focus, an actual image is made at infinity. The image size is much greater than the object's size. When an object is situated at infinity, the actual image is made at the focus. The image size is much more petite than the object size.
Complete step by step answer:
If we take the object near the lens in the convex lens, the image size keeps on increasing. As we make the object closer to the lens, we get the image enlarged. So, we can tell that the images created can be of different types. We can have diminished inverted images, small sizes inverted images, enlarged inverted images, enlarged erect images. So, in a convex lens, there is a possibility of getting an actual and inverted image.
Image creation in a convex lens can be described with the help of three principal rays.
$1$. The parallel rays to the principal axis move through the focal point after refraction by the lens.
$2$. The ray moving through the optical centre passes directly through the lens and continues without deviation.
$3$. The ray travels through the focal point and becomes parallel to the principal axis.
When an object is positioned beyond the centre of curvature $2F$, then a light ray AO which is parallel to the principal axis, moves through the focus F along the direction OF resulting refraction. Another ray of light AC crosses through the optical centre C and goes direct without any deviation. The two refracted rays meet each other at location A’, between the focus F and centre of curvature $2F$ on the different side of the lens. In this approach, a diminished, inverted, and real image A’B’ is formed.
So, the correct answer is “Option 1”.
Note: When an object is situated in between focus and pole, a virtual image is made. The size of the image is more significant than that of an object. When an object is set at the focus, an actual image is made at infinity. The image size is much greater than the object's size. When an object is situated at infinity, the actual image is made at the focus. The image size is much more petite than the object size.
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