
On hydrolysis, diborane produces:
A. ${H_3}B{O_2} + {H_2}{O_2}$
B. ${H_3}B{O_3} + {H_2}$
C. ${B_2}{O_3} + {O_2}$
D. ${H_3}B{O_3} + {H_2}{O_2}$
Answer
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Hint: To solve this question, first we should know the exact meaning of hydrolysis of anything that is a reaction of any compound with water. And after hydrolysis, it will produce Hydrogen only from the water.
Complete step by step answer:
Hydrolysis of diborane means that Diborane reacts with water.
And, when Diborane react with water, it produces boric acid and hydrogen, Diborane reacts violently with water to form hydrogen and boric acid:
${B_2}{H_6} + 6{H_2}O \to 2{H_3}B{O_3} + 6{H_2}$
Here, ${B_2}{H_6}$ is Diborane and $6{H_2}O$ is 6 molecules of water.
${H_3}B{O_3}$ is a Boric Acid and ${H_2}$ is hydrogen.
Diborane is a highly reactive and versatile reagent that has numerous applications. The Boron hydrides mix well with the air forming up explosive mixtures. This substance will ignite rapidly at room temperature. The other names for Diborane are boron ethane, diboron hexahydride. The structure of a Diborane molecule consists of four hydrogen atoms and that of two boron atoms coming on the same plane.
Diborane readily hydrolyzes in water to give hydrogen gas and boric acid. Most of the diborane are known to be flammable in air. Preparation Of Diborane. The action of a metal hydride with boron produced diborane. This approach is common in the industrial production of diborane.
So, the correct answer is Option B.
Note: We should observe how hydrolysis of anything works: They are portrayed by some water solvency because of their interest in hydrogen holding. In basic, Hydrolysis is a basic response with water. It may very well be a converse of water buildup where it includes the launch of a water atom when two particles structure together to shape a bigger atom.
Complete step by step answer:
Hydrolysis of diborane means that Diborane reacts with water.
And, when Diborane react with water, it produces boric acid and hydrogen, Diborane reacts violently with water to form hydrogen and boric acid:
${B_2}{H_6} + 6{H_2}O \to 2{H_3}B{O_3} + 6{H_2}$
Here, ${B_2}{H_6}$ is Diborane and $6{H_2}O$ is 6 molecules of water.
${H_3}B{O_3}$ is a Boric Acid and ${H_2}$ is hydrogen.
Diborane is a highly reactive and versatile reagent that has numerous applications. The Boron hydrides mix well with the air forming up explosive mixtures. This substance will ignite rapidly at room temperature. The other names for Diborane are boron ethane, diboron hexahydride. The structure of a Diborane molecule consists of four hydrogen atoms and that of two boron atoms coming on the same plane.
Diborane readily hydrolyzes in water to give hydrogen gas and boric acid. Most of the diborane are known to be flammable in air. Preparation Of Diborane. The action of a metal hydride with boron produced diborane. This approach is common in the industrial production of diborane.
So, the correct answer is Option B.
Note: We should observe how hydrolysis of anything works: They are portrayed by some water solvency because of their interest in hydrogen holding. In basic, Hydrolysis is a basic response with water. It may very well be a converse of water buildup where it includes the launch of a water atom when two particles structure together to shape a bigger atom.
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