Question

Ortho and para nitrophenols are more acidic than phenols. Draw the resonance structures of the corresponding phenoxide ions.

Answer 1

Hint: We know that if an electron withdrawing group will be present on phenol, it will make phenol more acidic as it will stabilize the phenoxide ion by the delocalization of the negative charge and also due to the inductive effect. The phenols, when they lose a proton, form the phenoxide ion. The negative charge present on the phenoxide ion will undergo resonance and is therefore very stable.

Complete step by step solution:
We determine the strength of an acid by the presence of electron withdrawing groups and also the position at which the groups are attached on the phenol.
Nitro group is an electron withdrawing group and shows both the effects i.e. the M-effect (mesomeric effect) also known as resonance and the I-effect or the inductive effect. The resonance effect causes the nitro group to withdraw electrons from the ortho and para positions. By inductive effect also it withdraws electrons but this effect is weaker than the resonance effect.
Nitro group by negative inductive effect withdraws electrons in the following order:
 $Ortho>meta>para$
The resonance structure of para nitrophenols: -

Resonance structure of ortho nitrophenols: -

Note:
Ortho nitrophenol is less acidic than para nitrophenol because of the intermolecular hydrogen bonding which makes the loss of proton very difficult. So, para nitrophenol is more acidic. On the other hand, the nitro group on increasing the acidity of phenol will decrease its basicity which means that nitrogen present in the nitro group will become less basic.