Answer
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Hint: According to the molecular orbital theory, the molecular orbital structure of oxygen contains two unpaired electrons in the antibonding orbitals. The molecule having unpaired electrons in the configuration is known as paramagnetic in nature.
Complete step by step answer:
The electronic configuration of oxygen (atomic number$z = 8$ ) in the ground state is:
As each oxygen atom has light electron so, the electronic configuration of oxygen molecule is:
${O_2} \to 1{S^2}{\sigma ^*}1{S^2}\sigma 2{S^2}{\sigma ^*}2{S^2}\pi 2{P_2}^2\pi 2{P_x}^2 = \pi 2P{y^2}$
${\pi ^*}2P{x^1} = {\pi ^*}2P{y^1}$
The bond – order of ${O_2}$ is two.
$\operatorname{Bond} order{\text{ = }}\dfrac{{{N_b} - {N_a}}}{2} = \dfrac{{8 - 4}}{2} = 2$
Bond – order shows the number of electrons present in anti – bonding molecular orbitals.
${O_2}$Has two bonds, one is sigma bond and other is pi-bonded.
The energy diagram of ${O_2}$molecule is:
The electrons in ${\pi ^*}2Px$ and ${\pi ^*}2Py$ remain unpaired. So, there are two unpaired electrons in ${O_2}$. Hence, it is paramagnetic in nature with two unpaired electrons.
So, the correct answer is Option C .
Additional information:
The molecular theory or MOT is based on chemical bonding and it was developed by F. Hund and R.S. Mulliken. It describes the structure and the properties of different molecules. The molecular orbital theory proved to be good as compared to valence bond theory because valence bond theory failed to explain how the molecules contain two or more than two equivalent bonds if in case their bond order lies in between single and double bonds.
Note: The molecular orbital theory can explain the existence of molecules on the basis of bond order, this holds good for diatomic molecules but not for the polyatomic molecules. Also, only with the help of molecular orbital theory one cannot describe the geometry and shape of the molecule.
Complete step by step answer:
The electronic configuration of oxygen (atomic number$z = 8$ ) in the ground state is:
As each oxygen atom has light electron so, the electronic configuration of oxygen molecule is:
${O_2} \to 1{S^2}{\sigma ^*}1{S^2}\sigma 2{S^2}{\sigma ^*}2{S^2}\pi 2{P_2}^2\pi 2{P_x}^2 = \pi 2P{y^2}$
${\pi ^*}2P{x^1} = {\pi ^*}2P{y^1}$
The bond – order of ${O_2}$ is two.
$\operatorname{Bond} order{\text{ = }}\dfrac{{{N_b} - {N_a}}}{2} = \dfrac{{8 - 4}}{2} = 2$
Bond – order shows the number of electrons present in anti – bonding molecular orbitals.
${O_2}$Has two bonds, one is sigma bond and other is pi-bonded.
The energy diagram of ${O_2}$molecule is:
The electrons in ${\pi ^*}2Px$ and ${\pi ^*}2Py$ remain unpaired. So, there are two unpaired electrons in ${O_2}$. Hence, it is paramagnetic in nature with two unpaired electrons.
So, the correct answer is Option C .
Additional information:
The molecular theory or MOT is based on chemical bonding and it was developed by F. Hund and R.S. Mulliken. It describes the structure and the properties of different molecules. The molecular orbital theory proved to be good as compared to valence bond theory because valence bond theory failed to explain how the molecules contain two or more than two equivalent bonds if in case their bond order lies in between single and double bonds.
Note: The molecular orbital theory can explain the existence of molecules on the basis of bond order, this holds good for diatomic molecules but not for the polyatomic molecules. Also, only with the help of molecular orbital theory one cannot describe the geometry and shape of the molecule.
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