Answer
Verified
441.3k+ views
HINT: To solve this, remember that ${{S}_{N}}1$ is an abbreviation for substitution nucleophilic unimolecular reaction. It is not a concerted mechanism and it takes place in two differentiable steps. Remember that after the formation of carbocation, there can be two possible products, the inversion as well as the retention product. Consider the absolute configuration to solve this question.
COMPLETE STEP BY STEP SOLUTION: Before answering this question, let us discuss what ${{S}_{N}}1$ reaction is. We know that ${{S}_{N}}1$ mechanism is nucleophilic substitution unimolecular reaction. In ${{S}_{N}}1$ reaction, SN basically stands for nucleophilic substitution and 1 stands for unimolecular. In ${{S}_{N}}1$ , the first step i.e. leaving of the leaving group and formation of the carbocation is the slow step and thus the rate determining step and the second step i.e. the attack of the nucleophile is the fast step. Now let us see the question given. Firstly, let us see the structure of (R)-2-octyl tosylate in the fischer form so that we can assign the absolute configuration. So, we know that the tosylate group is denoted as OTs. So, we can draw it as-
We can see that the least priority group is in horizontal position and thus the above structures in R-absolute configuration. Now, let us see its solvolysis via ${{S}_{N}}1$ mechanism.
Here, we can see that a planar carbocation is formed. So, the nucleophile can attack from any side and thus inversion as well as retention can take place here. Inversion will give us the S-product and retention will give us the R-product. So, we can write the mechanism as-
We will get the R as well as the S product in equal amounts.
Therefore, the correct answer is option [A] R-2-octanol and S-2-octanol in a 1:1 ratio
NOTE: We can describe the mechanism of ${{S}_{N}}1$ as a two-step process. In the first step of the mechanism, the leaving group leaves the substrate and this leads to the formation of a carbocation. We can write the reaction as-
Then, the nucleophile (Nu) attacks the carbocation and gives us the product.
The reactivity of compounds undergoing ${{S}_{N}}1$ depends upon 2 factors.
- The first factor is the effectiveness of the removal of the leaving group.
- The second factor is whether or not the carbocation formed is stable.
COMPLETE STEP BY STEP SOLUTION: Before answering this question, let us discuss what ${{S}_{N}}1$ reaction is. We know that ${{S}_{N}}1$ mechanism is nucleophilic substitution unimolecular reaction. In ${{S}_{N}}1$ reaction, SN basically stands for nucleophilic substitution and 1 stands for unimolecular. In ${{S}_{N}}1$ , the first step i.e. leaving of the leaving group and formation of the carbocation is the slow step and thus the rate determining step and the second step i.e. the attack of the nucleophile is the fast step. Now let us see the question given. Firstly, let us see the structure of (R)-2-octyl tosylate in the fischer form so that we can assign the absolute configuration. So, we know that the tosylate group is denoted as OTs. So, we can draw it as-
We can see that the least priority group is in horizontal position and thus the above structures in R-absolute configuration. Now, let us see its solvolysis via ${{S}_{N}}1$ mechanism.
Here, we can see that a planar carbocation is formed. So, the nucleophile can attack from any side and thus inversion as well as retention can take place here. Inversion will give us the S-product and retention will give us the R-product. So, we can write the mechanism as-
We will get the R as well as the S product in equal amounts.
Therefore, the correct answer is option [A] R-2-octanol and S-2-octanol in a 1:1 ratio
NOTE: We can describe the mechanism of ${{S}_{N}}1$ as a two-step process. In the first step of the mechanism, the leaving group leaves the substrate and this leads to the formation of a carbocation. We can write the reaction as-
Then, the nucleophile (Nu) attacks the carbocation and gives us the product.
The reactivity of compounds undergoing ${{S}_{N}}1$ depends upon 2 factors.
- The first factor is the effectiveness of the removal of the leaving group.
- The second factor is whether or not the carbocation formed is stable.
Recently Updated Pages
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Which one of the following places is not covered by class 10 social science CBSE
Trending doubts
Derive an expression for drift velocity of free electrons class 12 physics CBSE
Which are the Top 10 Largest Countries of the World?
Write down 5 differences between Ntype and Ptype s class 11 physics CBSE
The energy of a charged conductor is given by the expression class 12 physics CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Derive an expression for electric field intensity due class 12 physics CBSE
How do you graph the function fx 4x class 9 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Derive an expression for electric potential at point class 12 physics CBSE