Answer
362.1k+ views
Hint: Natural numbers are the numbers used for counting and ordering. They are whole, non-negative numbers which can be represented on a number line. A set of natural numbers is typically donated by N. So the natural numbers start from 1 and continue to infinity.
Complete step by step solution:
First $10$ natural numbers are $1,2,3,4,5,6,7,8,9$ and $10$.
So to find the product of the first 10 natural numbers we have to multiply them with each other.
Let the product of the first 10 natural numbers be donated by P.
So, $P=1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10$
$P= 2 \times 12 \times 30 \times 56 \times 90$
$P= 24 \times 1680 \times 90$
$P=40320 \times 90$
$P=3628800$
So the product of the first 10 natural numbers is $36,28,800.$
I would agree with Ram who says the product of the first 10 natural numbers ends with two zero as their product is $36,28,800.$
Whereas Venu is wrong who says it would end with only one zero as we have only one 10 because he is using the wrong logic as the product of $2$ and $5$ is also $10$, so it should end with two zeros.
Thus the product of the first $10$ natural numbers ends with two zeros at the end, so ram is correct and venu is wrong.
Note:
The product of the first $10$ natural numbers is $36,28,800$. So its product ends with two zeros at last. The natural numbers are non-zero, non- negative numbers. Also, to find the product of a set of numbers we have to multiply them with each other. Natural numbers are called natural because they are used for counting naturally.
Complete step by step solution:
First $10$ natural numbers are $1,2,3,4,5,6,7,8,9$ and $10$.
So to find the product of the first 10 natural numbers we have to multiply them with each other.
Let the product of the first 10 natural numbers be donated by P.
So, $P=1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10$
$P= 2 \times 12 \times 30 \times 56 \times 90$
$P= 24 \times 1680 \times 90$
$P=40320 \times 90$
$P=3628800$
So the product of the first 10 natural numbers is $36,28,800.$
I would agree with Ram who says the product of the first 10 natural numbers ends with two zero as their product is $36,28,800.$
Whereas Venu is wrong who says it would end with only one zero as we have only one 10 because he is using the wrong logic as the product of $2$ and $5$ is also $10$, so it should end with two zeros.
Thus the product of the first $10$ natural numbers ends with two zeros at the end, so ram is correct and venu is wrong.
Note:
The product of the first $10$ natural numbers is $36,28,800$. So its product ends with two zeros at last. The natural numbers are non-zero, non- negative numbers. Also, to find the product of a set of numbers we have to multiply them with each other. Natural numbers are called natural because they are used for counting naturally.
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