
SI unit of radioactivity is Bq which is equal to 1dps. If true enter 1, else enter 0
Answer
586.8k+ views
Hint: The radioactivity is based on the phenomenon of the disintegration of nuclei of the atom. SI unit is given as disintegration per second or decay per second. The other units of radioactivity are Curie and Rutherford.
Complete answer:
Let us first understand radioactivity:
Radioactivity: radioactivity is the phenomenon of spontaneous disintegration of the nucleus of an atom with the emission of one or more penetrating radiations like\[\alpha -particles\], \[\beta -particles\] \[\text{or }\gamma -particles\]
A naturally occurring heavy nucleus is unstable. It spontaneously emits a particle, without the stimulus of any outside agency, transforming itself into a different nucleus. Such a nucleus is said to be radioactive and the process of transformation is radioactive decay. The process is spontaneous in the sense that it occurs by itself. It cannot be initiated, stopped, accelerated, or retarded by changing.
(a)- chemical condition or
(b)- physical conditions like temperature, pressure, etc. other than the nuclear bombardment.
The SI unit of radioactivity is Becquerel, named after the discoverer of radioactivity, Henry Becquerel.
One Becquerel is defined as the decay rate of disintegration per second.
1 Becquerel = 1Bq = 1 decay per second = 1 dps.
Hence, it is true.
Additional information:
There are 2 more units of radioactivity:
Curie (Ci)= one curie is the rate of\[3.7\text{x}{{10}^{10}}\] disintegration per second.
It can be formulated as:
\[1\text{ }curie=1\text{ }Ci=3.7\text{x}{{10}^{10}}dps=3.7\text{x}{{10}^{10}}Bq\]
Rutherford (rd)= One Rutherford is the decay rate of \[{{10}^{6}}\]disintegrations per second.
It can be formulated as:
\[1\text{ }rd={{10}^{6}}dps={{10}^{6}}Bq\]
Note: The conversion of both the units into the SI unit should be correctly done. Becquuerel studied the electrical nature of the radioactive radiations and with his analysis he concluded that the radiations have three components alpha, beta and gamma rays.
Complete answer:
Let us first understand radioactivity:
Radioactivity: radioactivity is the phenomenon of spontaneous disintegration of the nucleus of an atom with the emission of one or more penetrating radiations like\[\alpha -particles\], \[\beta -particles\] \[\text{or }\gamma -particles\]
A naturally occurring heavy nucleus is unstable. It spontaneously emits a particle, without the stimulus of any outside agency, transforming itself into a different nucleus. Such a nucleus is said to be radioactive and the process of transformation is radioactive decay. The process is spontaneous in the sense that it occurs by itself. It cannot be initiated, stopped, accelerated, or retarded by changing.
(a)- chemical condition or
(b)- physical conditions like temperature, pressure, etc. other than the nuclear bombardment.
The SI unit of radioactivity is Becquerel, named after the discoverer of radioactivity, Henry Becquerel.
One Becquerel is defined as the decay rate of disintegration per second.
1 Becquerel = 1Bq = 1 decay per second = 1 dps.
Hence, it is true.
Additional information:
There are 2 more units of radioactivity:
Curie (Ci)= one curie is the rate of\[3.7\text{x}{{10}^{10}}\] disintegration per second.
It can be formulated as:
\[1\text{ }curie=1\text{ }Ci=3.7\text{x}{{10}^{10}}dps=3.7\text{x}{{10}^{10}}Bq\]
Rutherford (rd)= One Rutherford is the decay rate of \[{{10}^{6}}\]disintegrations per second.
It can be formulated as:
\[1\text{ }rd={{10}^{6}}dps={{10}^{6}}Bq\]
Note: The conversion of both the units into the SI unit should be correctly done. Becquuerel studied the electrical nature of the radioactive radiations and with his analysis he concluded that the radiations have three components alpha, beta and gamma rays.
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