
How do you simplify: \[\left( 7-6i \right)\left( -8+3i \right)\]?
Answer
534k+ views
Hint: Assume the value of the given expression as ‘E’. Multiply each term of the first expression (7 – 6i) with each term of the second expression (-8 + 3i). Finally, use the relation: - \[i=\sqrt{-1}\] and \[{{i}^{2}}=-1\], where ‘i’ is the imaginary number, for further simplification of ‘E’ and get the answer.
Complete step by step solution:
Here, we have been provided with the expression \[\left( 7-6i \right)\left( -8+3i \right)\] and we have been asked to simplify it.
Now, let us assume the given expression as ‘E’. So, we have,
\[\Rightarrow E=\left( 7-6i \right)\left( -8+3i \right)\]
Here we have to multiply each term of the first expression (7 – 6i) with each term of the second expression (-8 +3i) to get the answer. So, we have,
\[\begin{align}
& \Rightarrow E=-56+21i+48i-18{{i}^{2}} \\
& \Rightarrow E=-56+69i-18{{i}^{2}} \\
\end{align}\]
Now, here we can see that in the above expression we have an alphabet ‘i’, actually it is the notation for the imaginary number \[\sqrt{-1}\]. ‘i’ is the solution of the quadratic equation \[{{x}^{2}}+1=0\]. There are no real solutions of this quadratic equation and therefore the concept of imaginary numbers and complex numbers arises. A complex number is written in general form as: - \[z=a+ib\], where ‘z’ is the notation of complex numbers, ‘a’ is the real part and ‘ib’ is the imaginary part. Here, \[i=\sqrt{-1}\].
Now, let us come back to the expression ‘E’. Since, \[i=\sqrt{-1}\], therefore on squaring both the sides, we get,
\[\Rightarrow {{i}^{2}}=-1\]
So, substituting the value of \[{{i}^{2}}\] in expression ‘E’, we get,
\[\begin{align}
& \Rightarrow E=-56+69i-18\times \left( -1 \right) \\
& \Rightarrow E=-56+69i+18 \\
& \Rightarrow E=-38+69i \\
\end{align}\]
Hence, the above obtained value is the simplified form and our answer.
Note: One must not consider ‘i’ as any variable or just an alphabet. Remember that ‘i’ always denotes the imaginary number \[\sqrt{-1}\] in the topic ‘complex numbers’. You must remember certain algebraic identities and the formulas of the topic ‘exponents and power’ like: - \[{{a}^{m}}\times {{a}^{n}}={{a}^{m-n}},{{a}^{m}}\div {{a}^{n}}{{=}^{m-n}},{{\left( {{a}^{m}} \right)}^{n}}={{a}^{m\times n}}\], because these formulas are frequently used in the topic ‘complex numbers’. Remember the concepts of complex numbers and their general forms.
Complete step by step solution:
Here, we have been provided with the expression \[\left( 7-6i \right)\left( -8+3i \right)\] and we have been asked to simplify it.
Now, let us assume the given expression as ‘E’. So, we have,
\[\Rightarrow E=\left( 7-6i \right)\left( -8+3i \right)\]
Here we have to multiply each term of the first expression (7 – 6i) with each term of the second expression (-8 +3i) to get the answer. So, we have,
\[\begin{align}
& \Rightarrow E=-56+21i+48i-18{{i}^{2}} \\
& \Rightarrow E=-56+69i-18{{i}^{2}} \\
\end{align}\]
Now, here we can see that in the above expression we have an alphabet ‘i’, actually it is the notation for the imaginary number \[\sqrt{-1}\]. ‘i’ is the solution of the quadratic equation \[{{x}^{2}}+1=0\]. There are no real solutions of this quadratic equation and therefore the concept of imaginary numbers and complex numbers arises. A complex number is written in general form as: - \[z=a+ib\], where ‘z’ is the notation of complex numbers, ‘a’ is the real part and ‘ib’ is the imaginary part. Here, \[i=\sqrt{-1}\].
Now, let us come back to the expression ‘E’. Since, \[i=\sqrt{-1}\], therefore on squaring both the sides, we get,
\[\Rightarrow {{i}^{2}}=-1\]
So, substituting the value of \[{{i}^{2}}\] in expression ‘E’, we get,
\[\begin{align}
& \Rightarrow E=-56+69i-18\times \left( -1 \right) \\
& \Rightarrow E=-56+69i+18 \\
& \Rightarrow E=-38+69i \\
\end{align}\]
Hence, the above obtained value is the simplified form and our answer.
Note: One must not consider ‘i’ as any variable or just an alphabet. Remember that ‘i’ always denotes the imaginary number \[\sqrt{-1}\] in the topic ‘complex numbers’. You must remember certain algebraic identities and the formulas of the topic ‘exponents and power’ like: - \[{{a}^{m}}\times {{a}^{n}}={{a}^{m-n}},{{a}^{m}}\div {{a}^{n}}{{=}^{m-n}},{{\left( {{a}^{m}} \right)}^{n}}={{a}^{m\times n}}\], because these formulas are frequently used in the topic ‘complex numbers’. Remember the concepts of complex numbers and their general forms.
Recently Updated Pages
Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

State the principle of an ac generator and explain class 12 physics CBSE

Give 10 examples of unisexual and bisexual flowers

Sketch the electric field lines in case of an electric class 12 physics CBSE

