Question

Solve ${(56)^2} - {(55)^2}$

Answer 1

Hint: First, we will see what multiplication is, Multiplicand refers to the number multiplied. The multiplier is the number that refers to the number which multiplies the first number
Subtraction operation, which is the minus of two or more than two numbers or values but here comes with the condition that in subtraction the greater number sign will stay constant example $2 - 3 = - 1$ three has the greater sign with negative thus the resultant answer is negative if suppose three is positive and two is negative then the resultant answer will be positive.

Complete step by step answer:
Now by the use of the multiplication operation, here we define the square.
Square is the number that is multiplied by itself twice like ${2^2} = 4$, here two square is the value that multiplied two into times of two then yields four.
Hence by the three definitions, we can able to further solve the given problem,
Firsts using the square terms for the first value ${(56)^2} = 56 \times 56$(multiplied itself by two times)
Now by the use of multiplication operation, we get, ${(56)^2} = 56 \times 56 \Rightarrow 3136$
again, using the square terms for the second value ${(55)^2} = 55 \times 55$(multiplied itself by two times)
Now by the use of multiplication operation, we get, ${(55)^2} = 55 \times 55 \Rightarrow 3025$
Thus, we get for, ${(56)^2} - {(55)^2} = 3136 - 3025$
Now by the use of subtraction operation, we get ${(56)^2} - {(55)^2} = 3136 - 3025 \Rightarrow 111$
Therefore, after using the multiplication, subtraction, and square we get ${(56)^2} - {(55)^2} = 111$

Note: We can solve it using algebraic identity $(a)^2-(b)^2=(a+b)(a-b)$.
 Addition is the sum of two or more than two numbers, or values, or variables, and in addition, if we sum the two or more numbers a new frame of the number will be found.
The inverse of the multiplication method is called the division.