
Solve the following equation:
3x + 2(x + 2) = 20(2x - 5).
Answer
615.3k+ views
Hint: In order to solve this problem we have to transpose all the coefficients of x on one side of ‘=’ sign. Then we will get the value of x and the equation is solved.
Complete step-by-step answer:
The given equations is
3x + 2(x + 2) = 20(2x - 5).
On solving the equation we get,
3x + 2x + 4 = 40x – 100
Taking all the terms containing x on one side we get the equation as:
40x – 3x – 2x = 100 + 4
35x = 104
So, ${\text{x = }}\dfrac{{104}}{{35}}$.
The value of x obtained is ${\text{x = }}\dfrac{{104}}{{35}}$.
Note: To solve such equations you need to find the variables present in it by solving algebraically. You need to know that when a positive term is transposed from one side of ‘equal to’ sign then it becomes negative and vice-versa and when multiplied term transposed from one side of ‘equal to’ sign then it goes on division and vice-versa. Knowing this your problem will be solved.
Complete step-by-step answer:
The given equations is
3x + 2(x + 2) = 20(2x - 5).
On solving the equation we get,
3x + 2x + 4 = 40x – 100
Taking all the terms containing x on one side we get the equation as:
40x – 3x – 2x = 100 + 4
35x = 104
So, ${\text{x = }}\dfrac{{104}}{{35}}$.
The value of x obtained is ${\text{x = }}\dfrac{{104}}{{35}}$.
Note: To solve such equations you need to find the variables present in it by solving algebraically. You need to know that when a positive term is transposed from one side of ‘equal to’ sign then it becomes negative and vice-versa and when multiplied term transposed from one side of ‘equal to’ sign then it goes on division and vice-versa. Knowing this your problem will be solved.
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