Srinivas wanted to purchase a table for his house so he went to a furniture shop. This furniture shop sells both wooden and plastics tables. These both types of tales are available in circular, rectangular and shapes. So, from the total of how many types of tables will he choose from?
(A) 2
(B) 3
(C) 5
(D) 6
Answer
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Hint:According to the question we have to consider first the type of material table is made up of. Then we consider the types of shape of the table available. Then we multiply both situations to get the total number tables from which Srinivas select the table.
Complete step-by-step answer:
According to the question, there are tables available made up of two types of material i.e. wooden and plastic.
\[\therefore \]Type of table shopkeeper sells=2
Table is available in three shapes they are circular, rectangular and square
\[\therefore \]Type of shapes of table available= 3
So, each shape is made up of two type of material i.e. wooden and plastic
\[\therefore \] Total number of different types of table = $2 \times 3 = 6$
So, the total number of tables available from which Srinivas have to choose are 6 types of table.
So, the correct answer is “Option D”.
Note:A combination determines the number of possible arrangements in a collection of items where the order of the selection does not matter. It can be defined as selection of n objects taken r at a time it is represented as ${}^nC_r$. In the above problem there are 6 objects (Both plastic and wooden material) out of which 1 object has to be selected i.e. ${}^6C_1$ which gives 6 ways of selection.
Complete step-by-step answer:
According to the question, there are tables available made up of two types of material i.e. wooden and plastic.
\[\therefore \]Type of table shopkeeper sells=2
Table is available in three shapes they are circular, rectangular and square
\[\therefore \]Type of shapes of table available= 3
So, each shape is made up of two type of material i.e. wooden and plastic
\[\therefore \] Total number of different types of table = $2 \times 3 = 6$
So, the total number of tables available from which Srinivas have to choose are 6 types of table.
So, the correct answer is “Option D”.
Note:A combination determines the number of possible arrangements in a collection of items where the order of the selection does not matter. It can be defined as selection of n objects taken r at a time it is represented as ${}^nC_r$. In the above problem there are 6 objects (Both plastic and wooden material) out of which 1 object has to be selected i.e. ${}^6C_1$ which gives 6 ways of selection.
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