Answer
Verified
440.4k+ views
Hint As temperature increases of a wire, it’s resistance also increases. We are having a relation given for change in resistance with respect to temperature. So we can get a solution using this equation.
Complete step by step answer
The temperature dependence of the resistance in the question is given as
$ \Rightarrow R = {R_0}\left( {1 + \alpha \Delta T} \right) $
Now, according to the question, we have $ {R_0} = 100\Omega $, $ R = 150\Omega $, $ {T_0} = {27^ \circ }C $, and $ T = {227^ \circ }C $ .
So, $ \Delta T = T - {T_0} $
$ \Rightarrow \Delta T = {227^ \circ }C - {27^ \circ }C = {200^ \circ }C $
Putting these values in (1) we get
$ \Rightarrow 150 = 100\left( {1 + 200\alpha } \right) $
$ \Rightarrow 200\alpha = 0.5 $
On solving we get
$ \Rightarrow \alpha = 2.5 \times {10^{ - 4}}{/^ \circ }C $
This value matches with the value given in the Statement 1.
But while deriving the expression for the variation of the resistance with the temperature, it is assumed that the change in temperature is very small. But in this case, the change in temperature is
$ \Rightarrow \Delta T = {200^ \circ }C $
This is a quite large value.
Also, while the derivation of the equation (1) is carried out, it is assumed that the change in resistance is very small compared to the original value, that is
$ \Rightarrow \left( {R - {R_0}} \right) < < {R_0} $
But in this case the change in resistance
$ \Rightarrow \left( {R - {R_0}} \right) = 150 - 100 $
$ \Rightarrow \left( {R - {R_0}} \right) = 50\Omega $
Which is comparable to the original value of resistance. So the above equation (1) cannot be applied to this case. Thus the value of $ \alpha $ which is obtained above is incorrect.
Thus the Statement 1 is False.
Also the Statement 2 is True at the same time due to the reasons already stated above.
Hence the correct answer is option D.
Note
Do not blindly jump to the conclusion that Statement 1 is correct after getting the value of $ \alpha $ same as that given in the Statement. That value is intentionally given to be the same. The question basically wants to judge the knowledge of the concept mentioned in the Statement 2.
Complete step by step answer
The temperature dependence of the resistance in the question is given as
$ \Rightarrow R = {R_0}\left( {1 + \alpha \Delta T} \right) $
Now, according to the question, we have $ {R_0} = 100\Omega $, $ R = 150\Omega $, $ {T_0} = {27^ \circ }C $, and $ T = {227^ \circ }C $ .
So, $ \Delta T = T - {T_0} $
$ \Rightarrow \Delta T = {227^ \circ }C - {27^ \circ }C = {200^ \circ }C $
Putting these values in (1) we get
$ \Rightarrow 150 = 100\left( {1 + 200\alpha } \right) $
$ \Rightarrow 200\alpha = 0.5 $
On solving we get
$ \Rightarrow \alpha = 2.5 \times {10^{ - 4}}{/^ \circ }C $
This value matches with the value given in the Statement 1.
But while deriving the expression for the variation of the resistance with the temperature, it is assumed that the change in temperature is very small. But in this case, the change in temperature is
$ \Rightarrow \Delta T = {200^ \circ }C $
This is a quite large value.
Also, while the derivation of the equation (1) is carried out, it is assumed that the change in resistance is very small compared to the original value, that is
$ \Rightarrow \left( {R - {R_0}} \right) < < {R_0} $
But in this case the change in resistance
$ \Rightarrow \left( {R - {R_0}} \right) = 150 - 100 $
$ \Rightarrow \left( {R - {R_0}} \right) = 50\Omega $
Which is comparable to the original value of resistance. So the above equation (1) cannot be applied to this case. Thus the value of $ \alpha $ which is obtained above is incorrect.
Thus the Statement 1 is False.
Also the Statement 2 is True at the same time due to the reasons already stated above.
Hence the correct answer is option D.
Note
Do not blindly jump to the conclusion that Statement 1 is correct after getting the value of $ \alpha $ same as that given in the Statement. That value is intentionally given to be the same. The question basically wants to judge the knowledge of the concept mentioned in the Statement 2.
Recently Updated Pages
Who among the following was the religious guru of class 7 social science CBSE
what is the correct chronological order of the following class 10 social science CBSE
Which of the following was not the actual cause for class 10 social science CBSE
Which of the following statements is not correct A class 10 social science CBSE
Which of the following leaders was not present in the class 10 social science CBSE
Garampani Sanctuary is located at A Diphu Assam B Gangtok class 10 social science CBSE
Trending doubts
A rainbow has circular shape because A The earth is class 11 physics CBSE
Which are the Top 10 Largest Countries of the World?
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
How do you graph the function fx 4x class 9 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
Who gave the slogan Jai Hind ALal Bahadur Shastri BJawaharlal class 11 social science CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE