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Suppose A takes twice as much time as B and thrice as much time as C to complete a work. If all of them work together, they can finish the work in 2 days. How much time B and C working together to finish it?

Answer
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Hint- If one person does a work in x days and another person does it in y days then together they can finish that work in xyx+y days.
Let’s take work done by A be x
A takes twice as much as B Therefore B takes half of what time A takes.
B=x2
A takes thrice as much as C. Therefore C takes one third of what time A takes.
C=x3
When all of them work together, they can finish work in 2 days.
1A+1B+1C=121x+2x+3x=126x=12
Now, Cross multiply
x=12
 Now, we calculate how much time taken by B to complete work.
B=x2=122B=6
B takes 6 days to complete work.
Now, we calculate how much time taken by C to complete work.
C=x3=123C=4
C takes 4 days to complete work.
Now, we calculate how much time taken by B and C to work together.
 B does work in 6 days and C does it in 4 days.
 If B and C can work together
1B+1C16+14
Take LCM
2+312512
So, If B and C work together they will take 125 days.

Note- Whenever we face such types of problems we use some important points. Like we calculate how much time taken by a single person to complete their work then we calculate how much time taken by persons when they work together.