Answer
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Hint: First, let the number of total arrows as $x$. Then, form the equations according to the given conditions. Solve the equation and eliminate the value which contradicts the given statement.
Complete step-by-step answer:
First of all, let the number of arrows carried by Arjun be $x$.
Then, according to the question,
It is given that Arjun uses half the number of total arrows to cut down the arrows thrown by Bheeshm, hence it is given by $\dfrac{x}{2}$.
And we know that he has used 6 arrows to kill the rath of the driver of Bheeshm.
Next, he also used 1 arrow to knock down the rath,
And, 1 arrow is used to knock down the flag and 1 arrow for the bow of Bheeshm.
Next, he used one more than 4 times the square root of arrows he laid Bheeshm on an arrow bed, given by $1 + 4\sqrt x $
Therefore, when we add all the arrows used by Arjun, it will be equal to $x$
Hence, we can write the sum of all the arrows as,
$
x = \dfrac{x}{2} + 6 + 1 + 1 + 1 + 1 + 4\sqrt x \\
\Rightarrow x = \dfrac{x}{2} + 10 + 4\sqrt x \\
$
On solving the above equation, we get,
$
x = \dfrac{x}{2} + 10 + 4\sqrt x \\
\Rightarrow 2x = x + 20 + 8\sqrt x \\
\Rightarrow x - 20 = 8\sqrt x \\
$
On squaring both sides we get,
$
\Rightarrow x - 20 = 8\sqrt x \\
\Rightarrow {x^2} + 400 - 40x = 64x \\
\Rightarrow {x^2} - 104x + 400 = 0 \\
$
Now, factorize the equation and solve for the value of \[x\].
$
\Rightarrow {x^2} - 104x + 400 = 0 \\
\Rightarrow {x^2} - 100x - 4x + 400 = 0 \\
\Rightarrow x\left( {x - 100} \right) - 4\left( {x - 100} \right) = 0 \\
\Rightarrow \left( {x - 4} \right)\left( {x - 100} \right) = 0 \\
\Rightarrow x = 4,100 \\
$
One answer is 4 and the other is 100.
But, the total number of arrows cannot be 4 as Arjun used 6 arrows to kill the rath of the driver of Bheeshm, so the number will be more than 6.
Hence, Arjun had 100 arrows.
Note: While solving the value of $x$, squaring both sides should be done by keeping only the square-root term on one side to avoid difficult calculations. Also, the value which satisfies all the conditions should be considered.
Complete step-by-step answer:
First of all, let the number of arrows carried by Arjun be $x$.
Then, according to the question,
It is given that Arjun uses half the number of total arrows to cut down the arrows thrown by Bheeshm, hence it is given by $\dfrac{x}{2}$.
And we know that he has used 6 arrows to kill the rath of the driver of Bheeshm.
Next, he also used 1 arrow to knock down the rath,
And, 1 arrow is used to knock down the flag and 1 arrow for the bow of Bheeshm.
Next, he used one more than 4 times the square root of arrows he laid Bheeshm on an arrow bed, given by $1 + 4\sqrt x $
Therefore, when we add all the arrows used by Arjun, it will be equal to $x$
Hence, we can write the sum of all the arrows as,
$
x = \dfrac{x}{2} + 6 + 1 + 1 + 1 + 1 + 4\sqrt x \\
\Rightarrow x = \dfrac{x}{2} + 10 + 4\sqrt x \\
$
On solving the above equation, we get,
$
x = \dfrac{x}{2} + 10 + 4\sqrt x \\
\Rightarrow 2x = x + 20 + 8\sqrt x \\
\Rightarrow x - 20 = 8\sqrt x \\
$
On squaring both sides we get,
$
\Rightarrow x - 20 = 8\sqrt x \\
\Rightarrow {x^2} + 400 - 40x = 64x \\
\Rightarrow {x^2} - 104x + 400 = 0 \\
$
Now, factorize the equation and solve for the value of \[x\].
$
\Rightarrow {x^2} - 104x + 400 = 0 \\
\Rightarrow {x^2} - 100x - 4x + 400 = 0 \\
\Rightarrow x\left( {x - 100} \right) - 4\left( {x - 100} \right) = 0 \\
\Rightarrow \left( {x - 4} \right)\left( {x - 100} \right) = 0 \\
\Rightarrow x = 4,100 \\
$
One answer is 4 and the other is 100.
But, the total number of arrows cannot be 4 as Arjun used 6 arrows to kill the rath of the driver of Bheeshm, so the number will be more than 6.
Hence, Arjun had 100 arrows.
Note: While solving the value of $x$, squaring both sides should be done by keeping only the square-root term on one side to avoid difficult calculations. Also, the value which satisfies all the conditions should be considered.
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