![SearchIcon](https://vmkt.vedantu.com/vmkt/PROD/png/bdcdbbd8-08a7-4688-98e6-4aa54e5e0800-1733305962725-4102606384256179.png)
What will be the area of cross-section of a wire if its length is 1 m, its resistance is 23\[\Omega \] and the resistivity of material of the wire is \[1.84\times {{10}^{-6}}\Omega m\]?
Answer
463.2k+ views
Hint: We need to understand and apply the correct relations between the given physical parameters such as the resistance, resistivity of the material and length of the wire to find the unknown area of cross-section of the given wire to solve this problem.
Complete answer:
We know from Ohm's law that the resistance for a wire is the property which is constant for any range of potential drop and the corresponding current flow through the wire. From the Ohm’s law, we know that –
\[\begin{align}
& V\propto I \\
& \text{and,} \\
& V=IR \\
\end{align}\]
Here, the resistance is the constant of proportionality that balances and connects the voltage drop across the wire and the current through it.
The resistance is defined as the opposing effect experienced by the electrons in the movement under an applied external potential difference. It is dependent on the length of the wire, the area of cross-section of the wire and the nature of the wire.
From experiments, we have derived that the resistance increases with the length of the conductor and decreases with increasing area of cross-section of the wire. We can mathematically write this as –
\[\begin{align}
& R\propto \dfrac{l}{A} \\
& \Rightarrow R=\rho \dfrac{l}{A} \\
\end{align}\]
The constant of proportionality is the resistivity of the material. It is a characteristic property of the material that doesn’t change with any physical changes except for temperature.
The area of cross-section of the given resistor can be found from this relation as –
\[\begin{align}
& R=\rho \dfrac{l}{A} \\
& \Rightarrow A=\dfrac{\rho l}{R} \\
& \Rightarrow A=\dfrac{1.84\times {{10}^{-6}}\times 1}{23} \\
& \therefore A=8\times {{10}^{-8}}{{m}^{2}} \\
\end{align}\]
The area of cross-section of the given wire is –
\[A=8\times {{10}^{-8}}{{m}^{2}}\]
Note:
The resistance of a conducting material is dependent on the physical dimensions such as the length of the wire and it’s area of cross-section, whereas the resistivity is a material property which can change only with a change in temperature.
Complete answer:
We know from Ohm's law that the resistance for a wire is the property which is constant for any range of potential drop and the corresponding current flow through the wire. From the Ohm’s law, we know that –
\[\begin{align}
& V\propto I \\
& \text{and,} \\
& V=IR \\
\end{align}\]
Here, the resistance is the constant of proportionality that balances and connects the voltage drop across the wire and the current through it.
The resistance is defined as the opposing effect experienced by the electrons in the movement under an applied external potential difference. It is dependent on the length of the wire, the area of cross-section of the wire and the nature of the wire.
From experiments, we have derived that the resistance increases with the length of the conductor and decreases with increasing area of cross-section of the wire. We can mathematically write this as –
\[\begin{align}
& R\propto \dfrac{l}{A} \\
& \Rightarrow R=\rho \dfrac{l}{A} \\
\end{align}\]
The constant of proportionality is the resistivity of the material. It is a characteristic property of the material that doesn’t change with any physical changes except for temperature.
The area of cross-section of the given resistor can be found from this relation as –
\[\begin{align}
& R=\rho \dfrac{l}{A} \\
& \Rightarrow A=\dfrac{\rho l}{R} \\
& \Rightarrow A=\dfrac{1.84\times {{10}^{-6}}\times 1}{23} \\
& \therefore A=8\times {{10}^{-8}}{{m}^{2}} \\
\end{align}\]
The area of cross-section of the given wire is –
\[A=8\times {{10}^{-8}}{{m}^{2}}\]
Note:
The resistance of a conducting material is dependent on the physical dimensions such as the length of the wire and it’s area of cross-section, whereas the resistivity is a material property which can change only with a change in temperature.
Recently Updated Pages
Glucose when reduced with HI and red Phosphorus gives class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The highest possible oxidation states of Uranium and class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Find the value of x if the mode of the following data class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which of the following can be used in the Friedel Crafts class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A sphere of mass 40 kg is attracted by a second sphere class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Statement I Reactivity of aluminium decreases when class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
10 examples of friction in our daily life
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The correct order of melting point of 14th group elements class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Prokaryotic Cells and Eukaryotic Cells
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
State and prove Bernoullis theorem class 11 physics CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What organs are located on the left side of your body class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)