Answer
Verified
481.5k+ views
Hint: Try to understand the concept of graphs between two physical quantities. Draw an acceleration-time graph. Try to find the area of the graph with the help of physical notations. Then we can find our answer.
Complete step by step answer:
An acceleration-time graph is represented as the acceleration on the y-axis or the vertical axis and time in the x-axis or the horizontal axis. The value of the graph at a particular time will give us the acceleration of the object at that point of time.
Slope of an acceleration-time graph is known as a jerk. It gives us the rate of change of acceleration.
We can find the area under the acceleration-time graph for a certain time interval.
Area under the graph can be defined as, $\text{area }=\Delta a\times \Delta t$
Where, $\Delta t$ is the time interval and $\Delta a$ the change in acceleration in that time interval.
Now we can find acceleration as,
$\Delta a=\dfrac{\Delta v}{\Delta t}$
So, by multiplying both sides of equation by $\Delta t$ , we can write,
$\Delta a\times \Delta t=\Delta v$
So, the area under the acceleration-time graph can be given as,
$\text{area }=\Delta a\times \Delta t=\Delta v$
Which is the rate of change of velocity.
So, the area under any acceleration time graph at a certain time interval will give us the rate of change of velocity.
The correct option is (a).
Note: For a constant acceleration we will get a linear graph parallel to the time axis. If we have a uniformly increasing acceleration, we will get a straight line with a slope. For non-uniform acceleration we won’t get a straight-line graph.
Complete step by step answer:
An acceleration-time graph is represented as the acceleration on the y-axis or the vertical axis and time in the x-axis or the horizontal axis. The value of the graph at a particular time will give us the acceleration of the object at that point of time.
Slope of an acceleration-time graph is known as a jerk. It gives us the rate of change of acceleration.
We can find the area under the acceleration-time graph for a certain time interval.
Area under the graph can be defined as, $\text{area }=\Delta a\times \Delta t$
Where, $\Delta t$ is the time interval and $\Delta a$ the change in acceleration in that time interval.
Now we can find acceleration as,
$\Delta a=\dfrac{\Delta v}{\Delta t}$
So, by multiplying both sides of equation by $\Delta t$ , we can write,
$\Delta a\times \Delta t=\Delta v$
So, the area under the acceleration-time graph can be given as,
$\text{area }=\Delta a\times \Delta t=\Delta v$
Which is the rate of change of velocity.
So, the area under any acceleration time graph at a certain time interval will give us the rate of change of velocity.
The correct option is (a).
Note: For a constant acceleration we will get a linear graph parallel to the time axis. If we have a uniformly increasing acceleration, we will get a straight line with a slope. For non-uniform acceleration we won’t get a straight-line graph.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE