
The atomic number of chromium is 24. Its electronic configuration in ground state is $1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,4{s^1}\,3{d^5}$. Chromium atom by losing 3 electrons from ${\text{C}}{{\text{r}}^{3 + }}$ ions. A chromium atom contains $17\% $ more neutron than the protons. Now answer the following questions.
The number of unpaired electrons in ${\text{C}}{{\text{r}}^{3 + }}$ ions is:
A. 3
B. 6
C. 5
D. 1
Answer
560.1k+ views
Hint: The arrangement of electrons in the energy levels around the nucleus of an atom is known as the electronic configuration. The electrons fill up in the energy levels according to the Aufbau’s principle. We can determine the number of unpaired electrons of ${\text{C}}{{\text{r}}^{3 + }}$ ion from the electronic configuration.
Complete step by step solution:
We are given that the atomic number of chromium is 24.
The Aufbau’s principle states that in the ground state of the atoms, the orbitals are filled with electrons in order of the increasing energies. The order of energy of different orbitals in an atom is as follows:
$1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d$ and so on.
Thus, the electronic configuration of chromium is as follows:
$1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,4{s^1}\,3{d^5}$
We know that the chromium atom by losing 3 electrons from ${\text{C}}{{\text{r}}^{3 + }}$ ions. The three electrons are lost from the valence orbitals of the chromium atom. One electron is lost from the 4s orbital and two electrons are lost from the 3d orbital.
Thus, the electronic configuration of ${\text{C}}{{\text{r}}^{3 + }}$ ion is as follows:
$1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,4{s^0}\,3{d^3}$
The total capacity of the d-orbital is ten electrons. Thus, all the three electrons in the d-orbital are unpaired.
Thus, the number of unpaired electrons in ${\text{C}}{{\text{r}}^{3 + }}$ ions is 3.
Thus, the correct option is (A) 3.
Note:
Other rules that explain the electronic configuration are as follows:
1. Pauli’s exclusion principle: The Pauli’s exclusion principle states that the two electrons in an atom cannot have the same set of all four quantum numbers.
2. Hund’s rule of maximum multiplicity: The Hund’s rule of maximum multiplicity states that when several orbitals of equal energy are available, the electrons first fill all the orbitals singly before pairing in any of these orbitals.
Complete step by step solution:
We are given that the atomic number of chromium is 24.
The Aufbau’s principle states that in the ground state of the atoms, the orbitals are filled with electrons in order of the increasing energies. The order of energy of different orbitals in an atom is as follows:
$1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d$ and so on.
Thus, the electronic configuration of chromium is as follows:
$1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,4{s^1}\,3{d^5}$
We know that the chromium atom by losing 3 electrons from ${\text{C}}{{\text{r}}^{3 + }}$ ions. The three electrons are lost from the valence orbitals of the chromium atom. One electron is lost from the 4s orbital and two electrons are lost from the 3d orbital.
Thus, the electronic configuration of ${\text{C}}{{\text{r}}^{3 + }}$ ion is as follows:
$1{s^2}\,2{s^2}\,2{p^6}\,3{s^2}\,3{p^6}\,4{s^0}\,3{d^3}$
The total capacity of the d-orbital is ten electrons. Thus, all the three electrons in the d-orbital are unpaired.
Thus, the number of unpaired electrons in ${\text{C}}{{\text{r}}^{3 + }}$ ions is 3.
Thus, the correct option is (A) 3.
Note:
Other rules that explain the electronic configuration are as follows:
1. Pauli’s exclusion principle: The Pauli’s exclusion principle states that the two electrons in an atom cannot have the same set of all four quantum numbers.
2. Hund’s rule of maximum multiplicity: The Hund’s rule of maximum multiplicity states that when several orbitals of equal energy are available, the electrons first fill all the orbitals singly before pairing in any of these orbitals.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Prove that a parallelogram circumscribing a circle-class-12-maths-CBSE

Dihybrid cross is made between RRYY yellow round seed class 12 biology CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

The first microscope was invented by A Leeuwenhoek class 12 biology CBSE

Draw a ray diagram of compound microscope when the class 12 physics CBSE

