The car A of mass 1500 kg travelling at 25 m/s collides with another car B of mass 1000 kg travelling at 15 m/s in the same direction. After collision, the velocity of the car A becomes 20 m/s. The velocity of the car B after the collision is
Answer
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Hint: If the final momentum is the same as the initial momentum then the total momentum is conserved. If two bodies collide with each other, the collision between the two bodies is either elastic or inelastic. In both elastic and inelastic collision, the total momentum is conserved.
Complete step by step answer:
According to the law of conservation of momentum,
Initial momentum = Final momentum.
Thus, we write this as follows:
$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}……..(1)$
Here, $m_{1}=1500kg$ is the mass of the car A.
$m_{2}=1000kg$ is the mass of the car B.
$u_{1}=25m/s$ is the initial velocity of the car A.
$u_{2}=15m/s$ is the intial velocity of the car B.
$v_{1}=20m/s$ is the final velocity of the car A.
$v_{2}=?$ is the final velocity of the car B.
From equation (1),
$1500\times25+1000\times15=1500\times20+1000\times v_{2}$
$37500+15000=30000+1000\times v_{2}$
$52500=30000+1000\times v_{2}$
$1000\times v_{2}=52500-30000$
$1000\times v_{2}=22500$
$v_{2}=22.5\,m/s$
Thus, the speed of the car B is 22.5 m/s.
Note:
Velocity is the vector quantity, the numerical value of the velocity is either positive or negative depending on the direction stated for the motion of an object. If two objects are in the same direction then the velocity is positive, if both are moving in opposite directions then one of the velocity of the object is negative.
Complete step by step answer:
According to the law of conservation of momentum,
Initial momentum = Final momentum.
Thus, we write this as follows:
$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}……..(1)$
Here, $m_{1}=1500kg$ is the mass of the car A.
$m_{2}=1000kg$ is the mass of the car B.
$u_{1}=25m/s$ is the initial velocity of the car A.
$u_{2}=15m/s$ is the intial velocity of the car B.
$v_{1}=20m/s$ is the final velocity of the car A.
$v_{2}=?$ is the final velocity of the car B.
From equation (1),
$1500\times25+1000\times15=1500\times20+1000\times v_{2}$
$37500+15000=30000+1000\times v_{2}$
$52500=30000+1000\times v_{2}$
$1000\times v_{2}=52500-30000$
$1000\times v_{2}=22500$
$v_{2}=22.5\,m/s$
Thus, the speed of the car B is 22.5 m/s.
Note:
Velocity is the vector quantity, the numerical value of the velocity is either positive or negative depending on the direction stated for the motion of an object. If two objects are in the same direction then the velocity is positive, if both are moving in opposite directions then one of the velocity of the object is negative.
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