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The correct statement with regard to H2+ and H2
(A) Both H2+ and H2 are equally stable
(B) Both H2+ and H2 do not exist
(C) H2 is more stable than H2+
(D) H2+ is more stable than H2

Answer
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Hint :The composition of H2+ and H2 defines the stability order. H2+ does not include any electron in the antibonding molecular orbital. H2 includes electrons in antibonding molecular orbital.The stability can be easily identified from the electron presence in bonding and antibonding molecular orbital.

Complete Step By Step Answer:
The electron presence in anti-bonding orbital result in repulsion and decrease of stability
The stability order follows the molecular orbital theory
The formula for bonding order can be regarded as follows
Bonding order =12 (Number of bonding electrons -Number of antibonding electrons)
The number of antibonding electrons in H2+ is 0
The number of antibonding electrons in H2 is 1
The bonding order of H2+ is   =12(10)=0.5
The bonding order of H2 is =12(21)=0.5
 H2+ and H2 molecule have the same bond order
Presence of anti-bonding electron decreases the stability of the molecule
Therefore, H2+ is more stable than H2
Both H2+ and H2 are equally stable is incorrect statement
Both H2+ and H2 do not exist is incorrect statement
 H2 is more stable than H2+ is incorrect statement
The correct statement is H2+ is more stable than H2
Due to the electron-electron repulsion in H2 , the stability of H2 is low
The configuration of H2+ is 1 electron in 1 s bonding orbital
The configuration of H2 is 1 electron in 1 s bonding orbital and 1 electron in 1 s antibonding orbital
Even though the bond order of both H2+ and H2 are same, the stability is different
Therefore, H2+>H2 .

Note :
The stability order follows the molecular orbital theory. The electron presence in anti-bonding orbital results in repulsion and decrease of stability. Electron-electron repulsion in H2 , the stability of H2 is low.