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The cross-section ABCD of a swimming pool is a trapezium. It's width AB=14m depth at the shallow end is 1.5 m and at the deep end is 8 m. Find the area of the cross-section.

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Answer
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Hint: Construct the line DE perpendicular to the line BC. Find the area of the triangle DCE using the formula 12×base×height. Find the area of the rectangle DABE using the formula Base×height. Add the two to find the answer.

Complete step-by-step answer:

We will first construct the line DE perpendicular to the line BC. E is the intersection point of BCand DE, such that BCDE

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We know that the area of the triangle is 12×base×height. In the triangle DCE, the area can be calculated by substituting DE for base and CE.
12×CE×DE
From the figure it is evident that, DE=AB=14m and, CE+EB= 8m. Also, AD=EB=1.5m
Therefore CE=81.5=6.5m.
Substituting the value 6.5 for CE and 14 for DE in the equation 12×CE×DE.
Thus, area of the triangle DCE = 12×6.5×14=45.5m3

Also, the area of the rectangle is given by the formula Base×height.
Substituting the value of base with AB and AD for height in the formula Base×height to find the area of the rectangle ABED.
Area of ABED=AB×AD.
Substituting the value 14 for AB and 1.5 for AD, we get
Area of ABED= 14×1.5=21
The area of the cross-section ABCD is equal to the sum of the section ABED and section DCE.
Area of ABCD= Area of ABED+ Area of DCE.
Area of ABCD= 45.5+21=66.5m3
Thus the area of the cross section ABCD is 66.5m3.

Note: The formula of the area of the trapezium can also be used alternatively. The area of the trapezium is given by 12×(sum of the parallel sides)× height between the parallel sides.
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