
The cross-section of a swimming pool is a trapezium. It's width depth at the shallow end is 1.5 m and at the deep end is 8 m. Find the area of the cross-section.

Answer
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Hint: Construct the line perpendicular to the line . Find the area of the triangle using the formula . Find the area of the rectangle using the formula . Add the two to find the answer.
Complete step-by-step answer:
We will first construct the line perpendicular to the line . is the intersection point of and , such that
We know that the area of the triangle is . In the triangle , the area can be calculated by substituting for base and .
From the figure it is evident that, and, . Also,
Therefore .
Substituting the value 6.5 for and 14 for in the equation .
Thus, area of the triangle =
Also, the area of the rectangle is given by the formula .
Substituting the value of base with and for height in the formula to find the area of the rectangle .
Area of = .
Substituting the value 14 for and 1.5 for , we get
Area of =
The area of the cross-section is equal to the sum of the section and section .
Area of = Area of + Area of .
Area of =
Thus the area of the cross section is .
Note: The formula of the area of the trapezium can also be used alternatively. The area of the trapezium is given by .
Complete step-by-step answer:
We will first construct the line

We know that the area of the triangle is
From the figure it is evident that,
Therefore
Substituting the value 6.5 for
Thus, area of the triangle
Also, the area of the rectangle is given by the formula
Substituting the value of base with
Area of
Substituting the value 14 for
Area of
The area of the cross-section
Area of
Area of
Thus the area of the cross section
Note: The formula of the area of the trapezium can also be used alternatively. The area of the trapezium is given by
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