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The first Indian Remote Sensing satellite was launched in ___________.
A. 1957
B. 1988
C. 1960
D. 1975

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Answer
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Hint: IRS-1A is the name of the satellite and was effectively dispatched into a polar sun-coordinated circle on March 17 from the Soviet Cosmodrome at Baikonur. IRS-1A was the principal far off detecting mission to give symbolism to different land-based applications, for example, horticulture, ranger service, topography, and hydrology.

Complete answer:
IRS-1A was a section operational, part-test mission to create Indian ability in satellite symbolism. IRS-1A, the first of the arrangement of indigenous condition-of-craftsmanship distant detecting satellites, was effectively dispatched into a polar sun-coordinated circle on 17 March 1988 from the Soviet Cosmodrome at Baikonur. The mission's drawn-out target was to create indigenous distant detecting capacity. IRS-1A worked in a Sun-simultaneous circle.

On 17 March 1988, it had a perigee of 863 kilometers (536 mi), an apogee of 907 kilometers (564 mi), a tendency of $99.01^\circ $, and an orbital time of $102.7$ minutes. IRS-1A effectively finished its central goal in July 1996 in the wake of working for a very long time and 4 months. IRS-1A conveyed three "Direct Imaging Self Scanner" cameras, LISS-1, LISS-2A and LISS-2B, with a spatial goal of $72.5$ meters (238 ft) and $36.25$ meters $\left( {118.9ft} \right)$ separately. The three-pivot balanced out sun-simultaneous satellite conveyed LISS cameras which performed "push-brush" filtering in noticeable and close infrared groups to get pictures of the Earth. Neighbourhood central intersection time was fixed at around $10:30$ in the morning.

Thus, option (B) is correct.

Note: The rocket stage, estimating $1.56 \times 1.66 \times 1.10$ meters, had the payload module connected on the top and a deployable sun oriented cluster stowed on one or the other side. Demeanor control was given by four-energy wheels, two attractive forces, and an engine framework. Together, they gave an expected exactness of better than $ \pm 0.10^\circ $ in every one of the three tomahawks.