The first two terms of an A.P are \[{\text{27}}\] and \[{\text{24}}\] respectively. How many terms of the progression are to be added to get -30?
A.15
B.20
C.25
D.18
Answer
Verified
477.3k+ views
Hint: Term of an A.P is denoted as \[{{\text{T}}_{\text{n}}}{\text{ = a + (n - 1)d}}\] , so we substitute the given value of \[{\text{27}}\]and \[{\text{24}}\] in the equation and calculate the value of a and d then finally calculate the value of n for \[{{\text{S}}_{\text{n}}}{\text{ = - 30}}\].
Complete step-by-step answer:
As first two term of A.P are 27 and 24 so, equate it to \[{{\text{T}}_{\text{n}}}{\text{ = a + (n - 1)d}}\]
\[
{{\text{T}}_{\text{n}}}{\text{ = a + (n - 1)d}} \\
\Rightarrow {\text{27 = a and}} \\
\Rightarrow {\text{24 = a + d}} \\
\]
On solving both the above equation it is clear that
\[
{\text{a = 27, substituting its value in 24 = a + d, we get}} \\
{\text{24 = 27 + d}} \\
{\text{d = - 3}} \\
\]
Now , we have to calculate the number of terms up to which sums up to -30
\[
{{\text{S}}_{\text{n}}}{\text{ = }}\dfrac{{\text{n}}}{{\text{2}}}{\text{(2a + (n - 1)d)}} \\
{\text{On substituting the value of a, d and }}{{\text{S}}_{\text{n}}}{\text{,we get,}} \\
\Rightarrow {\text{ - 30 = }}\dfrac{{\text{n}}}{{\text{2}}}{\text{(2(27) + (n - 1)( - 3))}} \\
\Rightarrow {\text{ - 60 = n(57 - 3n)}} \\
{\text{On simplification we get,}} \\
\Rightarrow {\text{3}}{{\text{n}}^{\text{2}}}{\text{ - 57n - 60 = 0}} \\
{\text{On factorisation we get,}} \\
\Rightarrow {\text{3}}{{\text{n}}^{\text{2}}}{\text{ - 60n + 3n - 60 = 0}} \\
\Rightarrow {\text{3n(n - 20) + 3(n - 20) = 0}} \\
\Rightarrow {\text{(3n + 3)(n - 20) = 0}} \\
\Rightarrow {\text{n = 20 or n = - 1}} \\
\]
As value of n cannot be negative,
Hence option (b) is the correct answer.
Note: An arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant. For example, the sequence 1, 2, 3, 4, ... is an arithmetic progression with common difference 1
Use the data given in the question carefully, place them and form the equation and solve it so that the correct value of required can be obtained.
Complete step-by-step answer:
As first two term of A.P are 27 and 24 so, equate it to \[{{\text{T}}_{\text{n}}}{\text{ = a + (n - 1)d}}\]
\[
{{\text{T}}_{\text{n}}}{\text{ = a + (n - 1)d}} \\
\Rightarrow {\text{27 = a and}} \\
\Rightarrow {\text{24 = a + d}} \\
\]
On solving both the above equation it is clear that
\[
{\text{a = 27, substituting its value in 24 = a + d, we get}} \\
{\text{24 = 27 + d}} \\
{\text{d = - 3}} \\
\]
Now , we have to calculate the number of terms up to which sums up to -30
\[
{{\text{S}}_{\text{n}}}{\text{ = }}\dfrac{{\text{n}}}{{\text{2}}}{\text{(2a + (n - 1)d)}} \\
{\text{On substituting the value of a, d and }}{{\text{S}}_{\text{n}}}{\text{,we get,}} \\
\Rightarrow {\text{ - 30 = }}\dfrac{{\text{n}}}{{\text{2}}}{\text{(2(27) + (n - 1)( - 3))}} \\
\Rightarrow {\text{ - 60 = n(57 - 3n)}} \\
{\text{On simplification we get,}} \\
\Rightarrow {\text{3}}{{\text{n}}^{\text{2}}}{\text{ - 57n - 60 = 0}} \\
{\text{On factorisation we get,}} \\
\Rightarrow {\text{3}}{{\text{n}}^{\text{2}}}{\text{ - 60n + 3n - 60 = 0}} \\
\Rightarrow {\text{3n(n - 20) + 3(n - 20) = 0}} \\
\Rightarrow {\text{(3n + 3)(n - 20) = 0}} \\
\Rightarrow {\text{n = 20 or n = - 1}} \\
\]
As value of n cannot be negative,
Hence option (b) is the correct answer.
Note: An arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant. For example, the sequence 1, 2, 3, 4, ... is an arithmetic progression with common difference 1
Use the data given in the question carefully, place them and form the equation and solve it so that the correct value of required can be obtained.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success
Master Class 11 Computer Science: Engaging Questions & Answers for Success
Master Class 11 Maths: Engaging Questions & Answers for Success
Master Class 11 Social Science: Engaging Questions & Answers for Success
Master Class 11 Economics: Engaging Questions & Answers for Success
Master Class 11 Business Studies: Engaging Questions & Answers for Success
Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
The sequence of spore production in Puccinia wheat class 11 biology CBSE
What will happen when any type of copper vessel is class 11 chemistry CBSE
The number of structural isomers possible for C4H8 class 11 chemistry CBSE
The number of vertebrae in rabbit is a 40 b 33 c 44 class 11 biology CBSE
Why is the wurtz reaction not preferred for the preparation class 11 chemistry CBSE