
The intensity of gamma radiation from a given source is I. On passing through 36mm of lead, intensity is reduced to . The thickness of lead which reduces the intensity to is
A 6 mm
B 9 mm
C 18 mm
D 12 mm
Answer
489k+ views
Hint: Intensity of a ray passing through ‘x’ thickness of lead is given by I=IO . Where IO is the intensity from the source, x is the thickness of lead.
Complete step by step answer:
Given, intensity of gamma radiation from the source, IO= I
We know that the intensity of a ray passing through ‘x’ thickness of lead is given by I=IO
Given that when the thickness of lead i.e. x=36 mm, the intensity i.e. I=
Substituting the values given in the equation, we get,
Taking logarithm on both sides we get,
Using the values we get,
Now let the thickness of lead box be x so that intensity becomes, I=
Substituting the value of I and in the equation we get,
Then the above equation becomes,
Taking logarithm of both sides,
We know that
Then the equation becomes, -0.693=-0.0578x
So, the correct answer is “Option D”.
Additional Information:
The penetration power of gamma radiation is very high. They can easily pass through the body and thus pose a formidable radiation protection challenge, requiring shielding made from dense materials such as lead or concrete.
Note:
Logarithm value of common terms should be learnt by the students to solve such types of questions. Students should be familiar with some common results of logarithm. For example- , etc.
Complete step by step answer:
Given, intensity of gamma radiation from the source, IO= I
We know that the intensity of a ray passing through ‘x’ thickness of lead is given by I=IO
Given that when the thickness of lead i.e. x=36 mm, the intensity i.e. I=
Substituting the values given in the equation, we get,
Taking logarithm on both sides we get,
Using the values
Now let the thickness of lead box be x so that intensity becomes, I=
Substituting the value of I and
Then the above equation becomes,
Taking logarithm of both sides,
We know that
Then the equation becomes, -0.693=-0.0578x
So, the correct answer is “Option D”.
Additional Information:
The penetration power of gamma radiation is very high. They can easily pass through the body and thus pose a formidable radiation protection challenge, requiring shielding made from dense materials such as lead or concrete.
Note:
Logarithm value of common terms should be learnt by the students to solve such types of questions. Students should be familiar with some common results of logarithm. For example-
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