Answer
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Hint: In this question we need to explain the given elements above in the question, as giving a brief knowledge about this compound can help us to give a brief knowledge about such kinds of elements.
Complete answer:
Nickel carbonyl (IUPAC name: tetracarbonylnickel) is the organonickel compound with the recipe $Ni(CO)_4$. This dismal fluid is the vital carbonyl of nickel. It is a middle of the road in the Mond procedure for creating extremely high-virtue nickel and a reagent in organometallic science, in spite of the fact that the Mond Process has dropped out of basic utilization because of the wellbeing perils in working with the compound. Nickel carbonyl is one of the most hazardous substances yet experienced in nickel science because of its high poisonousness, aggravated with high instability and fast skin assimilation
The IUPAC name of $Ni(CO)_4$ is Tetracarbonyl nickel (0) since the oxidation state of carbonyl ligand is 0, so Ni will also be 0 and four ligand are bonded to central metal atom and
$[PtCl_4]^{2-}$
Tetrachloroplatinate(2-)
Note: In this answer we gave a brief explanation about both the required compounds and giving an explanation can also help us to gain such a type of answer. Explananing formulae would also help in the required solution.
Complete answer:
Nickel carbonyl (IUPAC name: tetracarbonylnickel) is the organonickel compound with the recipe $Ni(CO)_4$. This dismal fluid is the vital carbonyl of nickel. It is a middle of the road in the Mond procedure for creating extremely high-virtue nickel and a reagent in organometallic science, in spite of the fact that the Mond Process has dropped out of basic utilization because of the wellbeing perils in working with the compound. Nickel carbonyl is one of the most hazardous substances yet experienced in nickel science because of its high poisonousness, aggravated with high instability and fast skin assimilation
The IUPAC name of $Ni(CO)_4$ is Tetracarbonyl nickel (0) since the oxidation state of carbonyl ligand is 0, so Ni will also be 0 and four ligand are bonded to central metal atom and
$[PtCl_4]^{2-}$
Tetrachloroplatinate(2-)
Note: In this answer we gave a brief explanation about both the required compounds and giving an explanation can also help us to gain such a type of answer. Explananing formulae would also help in the required solution.
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