Answer
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Hint: In order to solve this problem you should know that the longest rod for a cuboid is equal to the length of the body diagonal of the cuboid.
Complete step-by-step answer:
Given,
Length(AB) = 8m 50cm = 8.5m
Breadth(EB) = 6m 25cm = 6.25m
Height(EF) = 4m 75cm = 4.75m
To find the length of body diagonal, we first need to find the length of a face diagonal AE and then find the body diagonal AF.
(using Pythagoras’s theorem)
In \[\Delta \]AEB,
$A{E^2} = A{B^2} + B{E^2}$
$
A{E^2} = {(8.5)^2} + {(6.25)^2} \\
AE = \sqrt {72.25 + 39.06} \\
AE = \sqrt {111.31} \\
AE = 10.5m \\
\\
$
Now to find the face diagonal AF
In \[\Delta \]AEF,
$
A{F^2} = A{E^2} + F{E^2} \\
A{F^2} = {(10.5)^2} + {(4.75)^2} \\
AF = \sqrt {111.31 + 22.56} \\
AF = \sqrt {133.87} \\
AF = 11.57m \\
$
Hence, the length of the longest rod for measurement is 11.57m.
Note: To solve such problems we must know the concept of longest rod and application of Pythagoras Theorem to find the body diagonal of the cuboid, as similarly the body diagonal of a cube can be found. Proceeding like this it will solve your problem.
Complete step-by-step answer:
Given,
Length(AB) = 8m 50cm = 8.5m
Breadth(EB) = 6m 25cm = 6.25m
Height(EF) = 4m 75cm = 4.75m
To find the length of body diagonal, we first need to find the length of a face diagonal AE and then find the body diagonal AF.
(using Pythagoras’s theorem)
In \[\Delta \]AEB,
$A{E^2} = A{B^2} + B{E^2}$
$
A{E^2} = {(8.5)^2} + {(6.25)^2} \\
AE = \sqrt {72.25 + 39.06} \\
AE = \sqrt {111.31} \\
AE = 10.5m \\
\\
$
Now to find the face diagonal AF
In \[\Delta \]AEF,
$
A{F^2} = A{E^2} + F{E^2} \\
A{F^2} = {(10.5)^2} + {(4.75)^2} \\
AF = \sqrt {111.31 + 22.56} \\
AF = \sqrt {133.87} \\
AF = 11.57m \\
$
Hence, the length of the longest rod for measurement is 11.57m.
Note: To solve such problems we must know the concept of longest rod and application of Pythagoras Theorem to find the body diagonal of the cuboid, as similarly the body diagonal of a cube can be found. Proceeding like this it will solve your problem.
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