Answer
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Hint: Resonance structures are hypothetical and do not represent any real molecule. The real structure of a molecule is a hybrid of the resonating structure.
Complete step by step answer:
Let us discuss the structure of benzene.
The structure of benzene cannot be explained by a single Lewis structure.
The structure of benzene is cyclic. It contains C-C single and C=C double bond and represented as
As per above representation benzene exhibits two bond lengths due to C-C and C=C bonds.
But it was experimentally determined that benzene has uniform bond length i.e., $139pm.$
This value is intermediate between C-C single $[154pm]$ and C=C double $[134pm]$bonds.
Therefore, benzene can be represented by energetically identical structure I and II.
Therefore, the structure of benzene cannot be represented by any of their structure.
It is a hybrid of these two resonating structures.
Therefore, from the above explanation the correct option is (B) 2.
Additional Information:
The energy of resonance hybrid is lower than that of its resonating structure.
The difference in energy between hybrid structure and resonating structure is called resonance energy.
The more the number of resonating structures the more is resonance energy.
Note:
In benzene each C-atom is $s{p^2}$ hybridized.
Two hybridized $s{p^2}$ orbitals form $\sigma $ bond and unhybridized orbitals of C-atom form $\pi $ bond.
With adjacent C-atoms by lateral overlap.
This explains equal possibility for formation of ${C_1} - {C_2},{C_3} - {C_4},{C_5} - {C_6}$$\pi $ bond or ${C_2} - {C_3},{C_4} - {C_5},{C_6} - {C_1}$$\pi $ bond.
The hybrid structure is represented by a circle inside the ring.
Complete step by step answer:
Let us discuss the structure of benzene.
The structure of benzene cannot be explained by a single Lewis structure.
The structure of benzene is cyclic. It contains C-C single and C=C double bond and represented as
As per above representation benzene exhibits two bond lengths due to C-C and C=C bonds.
But it was experimentally determined that benzene has uniform bond length i.e., $139pm.$
This value is intermediate between C-C single $[154pm]$ and C=C double $[134pm]$bonds.
Therefore, benzene can be represented by energetically identical structure I and II.
Therefore, the structure of benzene cannot be represented by any of their structure.
It is a hybrid of these two resonating structures.
Therefore, from the above explanation the correct option is (B) 2.
Additional Information:
The energy of resonance hybrid is lower than that of its resonating structure.
The difference in energy between hybrid structure and resonating structure is called resonance energy.
The more the number of resonating structures the more is resonance energy.
Note:
In benzene each C-atom is $s{p^2}$ hybridized.
Two hybridized $s{p^2}$ orbitals form $\sigma $ bond and unhybridized orbitals of C-atom form $\pi $ bond.
With adjacent C-atoms by lateral overlap.
This explains equal possibility for formation of ${C_1} - {C_2},{C_3} - {C_4},{C_5} - {C_6}$$\pi $ bond or ${C_2} - {C_3},{C_4} - {C_5},{C_6} - {C_1}$$\pi $ bond.
The hybrid structure is represented by a circle inside the ring.
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