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The percent of pure gold in 14 carat gold is about 58.3%. A 14 carat gold ring weighs 7.6 grams. How many grams of pure gold are in the ring?

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Last updated date: 25th Aug 2024
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Answer
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Hint: We will first use the percentage of pure gold to find the amount of pure gold if the ring weighs 1 gm. And then multiply the result to 7.6 to get the required answer.

Complete step-by-step answer:
We are given that the percent of pure gold in 14 carat gold is about 58.3%.
So, if we have an object which actually weighed 1 gm.
The amount of pure gold in it would have been found by using the formula given below:-
$Amount = \dfrac{{Percentage}}{{100}} \times Weight$, where amount is the required amount of pure gold in the object and weight is the total weight of the object.
The amount of pure gold in 1 gm ring will be:-
$Amount = \dfrac{{58.3}}{{100}} \times 1gm = 0.583gm$.
Now, since 1 gm ring contains 0.583 gm of pure gold.
Therefore, a 7.6 gm ring contains $(0.583 \times 7.6)gm = 4.4308gm$ of pure gold.

Hence, the ring has 4.4308 gms of pure gold in the product.

Note: Percent means out of one hundred. It is expressed and shown with the symbol "%". You may relate by the percentage you get in the result at the end of a semester or session as well. The percentage makes it easy to understand how much you have scored in the class in comparison to other students. Even if your exams were of 80 marks, you eventually get a result out of 100, that is possible because we convert the numbers in percent.