Answer
415.5k+ views
Hint: We need to find the focal length of the lens. For that we have a lens maker’s formula. We can substitute the given values of radius of curvature into the lens maker’s formula. Then we can find the focal length by simplifying and taking the reciprocal.
Formula used:
Lens maker’s formula
\[\dfrac{1}{f}=\left( \mu -1 \right)\left( \dfrac{1}{{{R}_{1}}}-\dfrac{1}{{{R}_{2}}} \right)\]
Complete step by step answer:
In the question we are given the radius of curvature of the convex surface of a Plano-convex lens.
A Plano-convex with radius of curvature of the convex surface = 10cm is given in the above figure.
We need to find the focal length of the lens.
The relation between radius of curvature and focal length of a lens is given by the lens maker’s formula.
It is given as,
\[\dfrac{1}{f}=\left( \mu -1 \right)\left( \dfrac{1}{{{R}_{1}}}-\dfrac{1}{{{R}_{2}}} \right)\], Where f = focal length of the lens, µ = refractive index of the material ${{R}_{1}}$ is the radius of curvature of the ${{1}^{st}}$ surface and ${{R}_{2}}$ is the radius of curvature of the ${{2}^{nd}}$ surface.
We have a Plano-convex lens, which means, one side of the lens is plane and the other side is convex.
Radius of curvature of the convex surface is given as 10 cm and the radius of curvature of the plane surface is infinity.
$\Rightarrow {{R}_{1}}=10cm$ And ${{R}_{2}}=\infty $
We are also given the refractive index $\mu =1.5$.
Applying these in the lens maker’s formula, we get,
\[\dfrac{1}{f}=\left( 1.5-1 \right)\left( \dfrac{1}{10}-\dfrac{1}{\infty } \right)\]
We know that \[\dfrac{1}{\infty }=0\]
\[\therefore \dfrac{1}{f}=\left( 0.5 \right)\left( \dfrac{1}{10} \right)=\dfrac{1}{20}\]
On taking the reciprocal, we get,
\[f=20\]
Therefore, the focal length of the lens is $20cm$.
Hence the correct answer is option B.
Note:
Plano convex lens is a type of convex lens with one spherical surface and a flat surface. The radius of curvature of the plane surface of a Plano-convex lens is infinite. Plano-convex lenses are used to focus parallel rays to a single point.
Formula used:
Lens maker’s formula
\[\dfrac{1}{f}=\left( \mu -1 \right)\left( \dfrac{1}{{{R}_{1}}}-\dfrac{1}{{{R}_{2}}} \right)\]
Complete step by step answer:
In the question we are given the radius of curvature of the convex surface of a Plano-convex lens.
![seo images](https://www.vedantu.com/question-sets/1b46e273-ef75-49bd-9ddd-46b193df14961540997652942818355.png)
A Plano-convex with radius of curvature of the convex surface = 10cm is given in the above figure.
We need to find the focal length of the lens.
The relation between radius of curvature and focal length of a lens is given by the lens maker’s formula.
It is given as,
\[\dfrac{1}{f}=\left( \mu -1 \right)\left( \dfrac{1}{{{R}_{1}}}-\dfrac{1}{{{R}_{2}}} \right)\], Where f = focal length of the lens, µ = refractive index of the material ${{R}_{1}}$ is the radius of curvature of the ${{1}^{st}}$ surface and ${{R}_{2}}$ is the radius of curvature of the ${{2}^{nd}}$ surface.
We have a Plano-convex lens, which means, one side of the lens is plane and the other side is convex.
Radius of curvature of the convex surface is given as 10 cm and the radius of curvature of the plane surface is infinity.
$\Rightarrow {{R}_{1}}=10cm$ And ${{R}_{2}}=\infty $
We are also given the refractive index $\mu =1.5$.
Applying these in the lens maker’s formula, we get,
\[\dfrac{1}{f}=\left( 1.5-1 \right)\left( \dfrac{1}{10}-\dfrac{1}{\infty } \right)\]
We know that \[\dfrac{1}{\infty }=0\]
\[\therefore \dfrac{1}{f}=\left( 0.5 \right)\left( \dfrac{1}{10} \right)=\dfrac{1}{20}\]
On taking the reciprocal, we get,
\[f=20\]
Therefore, the focal length of the lens is $20cm$.
Hence the correct answer is option B.
Note:
Plano convex lens is a type of convex lens with one spherical surface and a flat surface. The radius of curvature of the plane surface of a Plano-convex lens is infinite. Plano-convex lenses are used to focus parallel rays to a single point.
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