
The Schrodinger wave equation for hydrogen atom is:
\[{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}\left[ 2-\dfrac{{{r}_{0}}}{{{a}_{0}}} \right]{{e}^{-r/{{a}_{0}}}}\]
where, ${{a}_{0}}$ is Bohr radius. If the radial node in $2s$ be at ${{r}_{0}}$, then find $r$ in terms of ${{a}_{0}}$.
A.$\dfrac{{{a}_{0}}}{2}$
B.$2{{a}_{0}}$
C.$\sqrt{2}{{a}_{0}}$
D.$\dfrac{{{a}_{0}}}{\sqrt{2}}$
Answer
561.9k+ views
Hint:
Bohr radius is the distance between the nucleus and electron of an atom. The probability of an electron located at a particular point is given by the square value of the wave function. In this equation, ${{r}_{0}}$ is the radial node.
Complete step by step answer:
Here, it is given that the Schrodinger wave equation for hydrogen atom is:
\[{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}\left[ 2-\dfrac{{{r}_{0}}}{{{a}_{0}}} \right]{{e}^{-r/{{a}_{0}}}}\]
where, ${{a}_{0}}$ is Bohr radius, ${{r}_{0}}$ is the radial node and $\Psi $ is the wave function.
When wave function passes through zero, a node occurs. The electron has zero probability of being located at a node. The probability of an electron located at a particular point is given by the square value of the wave function. As we discussed that electron has zero probability of being located at a node, we can say that
\[|{{\Psi }_{2s}}{{|}^{2}}=0\]
Now, looking at the above equation, we can observe that, if the square of the value of wave function is equal to zero, then the value of $\left( 2-\dfrac{{{a}_{0}}}{{{r}_{0}}} \right)$ has to be equal to zero.
Since, $\dfrac{1}{4\sqrt{2}\pi }$ is a constant which cannot be equal to zero and the value of ${{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}$ and ${{e}^{-r/{{a}_{0}}}}$ will always be greater than zero.
So, therefore, we can write
$2-\dfrac{{{r}_{0}}}{{{a}_{0}}}=0$
On further simplifying, we get,
$\Rightarrow {{r}_{0}}=2{{a}_{0}}$
Therefore, the correct option is (B) $2{{a}_{0}}$.
Additional information:
-Schrodinger wave equation is an equation that is used to calculate the wave function of a quantum – mechanical system. The wave function is used to define the state of the system at each spatial position and time.
-Wave function is defined as the quantum state of an isolated quantum system. It is denoted with a symbol, $\Psi $
Note: A wave function node generally occurs at a point where wave function is zero, that means, the electron has zero probability of being located at a node.
-Bohr radius is the most probable distance between the electron and the nucleus.
Bohr radius is the distance between the nucleus and electron of an atom. The probability of an electron located at a particular point is given by the square value of the wave function. In this equation, ${{r}_{0}}$ is the radial node.
Complete step by step answer:
Here, it is given that the Schrodinger wave equation for hydrogen atom is:
\[{{\Psi }_{2s}}=\dfrac{1}{4\sqrt{2}\pi }{{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}\left[ 2-\dfrac{{{r}_{0}}}{{{a}_{0}}} \right]{{e}^{-r/{{a}_{0}}}}\]
where, ${{a}_{0}}$ is Bohr radius, ${{r}_{0}}$ is the radial node and $\Psi $ is the wave function.
When wave function passes through zero, a node occurs. The electron has zero probability of being located at a node. The probability of an electron located at a particular point is given by the square value of the wave function. As we discussed that electron has zero probability of being located at a node, we can say that
\[|{{\Psi }_{2s}}{{|}^{2}}=0\]
Now, looking at the above equation, we can observe that, if the square of the value of wave function is equal to zero, then the value of $\left( 2-\dfrac{{{a}_{0}}}{{{r}_{0}}} \right)$ has to be equal to zero.
Since, $\dfrac{1}{4\sqrt{2}\pi }$ is a constant which cannot be equal to zero and the value of ${{\left( \dfrac{1}{{{a}_{0}}} \right)}^{3/2}}$ and ${{e}^{-r/{{a}_{0}}}}$ will always be greater than zero.
So, therefore, we can write
$2-\dfrac{{{r}_{0}}}{{{a}_{0}}}=0$
On further simplifying, we get,
$\Rightarrow {{r}_{0}}=2{{a}_{0}}$
Therefore, the correct option is (B) $2{{a}_{0}}$.
Additional information:
-Schrodinger wave equation is an equation that is used to calculate the wave function of a quantum – mechanical system. The wave function is used to define the state of the system at each spatial position and time.
-Wave function is defined as the quantum state of an isolated quantum system. It is denoted with a symbol, $\Psi $
Note: A wave function node generally occurs at a point where wave function is zero, that means, the electron has zero probability of being located at a node.
-Bohr radius is the most probable distance between the electron and the nucleus.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
The computer jargonwwww stands for Aworld wide web class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Dihybrid cross is made between RRYY yellow round seed class 12 biology CBSE

What is virtual and erect image ?

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

List the two methodologies which were involved in the class 12 biology CBSE

