Answer
Verified
429.9k+ views
Hint:Here given that the satellite is revolving on a circular radius around the earth having a radius of $4R$, hence to find the time period of the satellite in which it completes its revolution the concept of Kepler’s law is used. Here the Kepler’s third law should be used to evaluate the time period of the satellite.
Complete step by step answer:
As discussed this question can be solved and the time period can be evaluated by using Kepler’s third law. Kepler’s third law states that the square of the time period given as ${T^2}$ of the revolution of the planet around the sun is directly proportional to the cube of the semi-major axis of the orbit that is the radius of the orbit of the planet which can be assumed as circular. Hence the relation between the time period of the planet $T$ and the radius $R$ of the orbit of the revolution of the planet can be given as
$\begin{array}{*{20}{c}}
{{T^2}}& \propto &{{R^3}}
\end{array}$ ……….. $(1)$
Now as it is given that the radius becomes $4R$ which is four times from the radius of another satellite hence substituting this in equation $(1)$ results in
$\begin{array}{*{20}{c}}
{{T^2}}& \propto &{{{\left( {4R} \right)}^3}}
\end{array}$
$\begin{array}{*{20}{c}}
{ \Rightarrow {T^2}}& \propto &{64{R^3}}
\end{array}$
On comparing the values on both sides as the square of the time period is proportional to the cube of the radius. Therefore the time period would be given as
$\begin{array}{*{20}{c}}
{64{T^2}}& \propto &{64{R^3}}
\end{array}$
$\begin{array}{*{20}{c}}
{ \Rightarrow {{\left( {8T} \right)}^2}}& \propto &{{{\left( {4R} \right)}^3}}
\end{array}$
Hence the time period of the satellite when the radius of the orbit becomes $4R$ is given $8T$.
Therefore option C is the correct answer.
Note:There are three Kepler's law that governs the planetary motions. The first Kepler's law states that the planets move around the sun in an elliptical orbit. The second law states that planets move around the sun as its foci and the third law as we had already discussed which is used to evaluate the time period of the satellite for the given radius.
Complete step by step answer:
As discussed this question can be solved and the time period can be evaluated by using Kepler’s third law. Kepler’s third law states that the square of the time period given as ${T^2}$ of the revolution of the planet around the sun is directly proportional to the cube of the semi-major axis of the orbit that is the radius of the orbit of the planet which can be assumed as circular. Hence the relation between the time period of the planet $T$ and the radius $R$ of the orbit of the revolution of the planet can be given as
$\begin{array}{*{20}{c}}
{{T^2}}& \propto &{{R^3}}
\end{array}$ ……….. $(1)$
Now as it is given that the radius becomes $4R$ which is four times from the radius of another satellite hence substituting this in equation $(1)$ results in
$\begin{array}{*{20}{c}}
{{T^2}}& \propto &{{{\left( {4R} \right)}^3}}
\end{array}$
$\begin{array}{*{20}{c}}
{ \Rightarrow {T^2}}& \propto &{64{R^3}}
\end{array}$
On comparing the values on both sides as the square of the time period is proportional to the cube of the radius. Therefore the time period would be given as
$\begin{array}{*{20}{c}}
{64{T^2}}& \propto &{64{R^3}}
\end{array}$
$\begin{array}{*{20}{c}}
{ \Rightarrow {{\left( {8T} \right)}^2}}& \propto &{{{\left( {4R} \right)}^3}}
\end{array}$
Hence the time period of the satellite when the radius of the orbit becomes $4R$ is given $8T$.
Therefore option C is the correct answer.
Note:There are three Kepler's law that governs the planetary motions. The first Kepler's law states that the planets move around the sun in an elliptical orbit. The second law states that planets move around the sun as its foci and the third law as we had already discussed which is used to evaluate the time period of the satellite for the given radius.
Recently Updated Pages
10 Examples of Evaporation in Daily Life with Explanations
10 Examples of Diffusion in Everyday Life
1 g of dry green algae absorb 47 times 10 3 moles of class 11 chemistry CBSE
What is the meaning of celestial class 10 social science CBSE
What causes groundwater depletion How can it be re class 10 chemistry CBSE
Under which different types can the following changes class 10 physics CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Which are the Top 10 Largest Countries of the World?
How do you graph the function fx 4x class 9 maths CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
In the tincture of iodine which is solute and solv class 11 chemistry CBSE
Why is there a time difference of about 5 hours between class 10 social science CBSE