Question

The two digit number $$\text{x}$$ is the digit at unit place and $$\text{y}$$ is the digit at unit place, then the number is :
$$\begin{gathered} \text{A}.10y+x \\ \text{B}.10x+y \\ \text{C}.10y-x \\ \text{D}.10-y \end{gathered}$$

Answer 1

Hint – Use the concept of ones and tens and make an equation, take an example of any two digit number.
It is a two digit number $$\text{x}$$ is the digit at unit place and $$\text{y}$$ is the digit at tens place .
Let us take an example of a two digit number $$51$$ so here $$1$$ is at the unit place and $$\text{5}$$ is digit at the tense place . So here,
 $x=1\mathrm{\&}y=5$ ……(i)
We can write $$51$$ as
$$51=50+1=10(5)+1$$
We can write the above equation as $$10y+x$$ ……(From (i))
Hence the correct option is A.
Note – In these types of questions we must have to know that, just left of decimal point is one place and left of one's place is a tens place. We should know that when we write the numbers of all these places in addition/subtraction then these numbers get multiplied by the number of their respective names, then aon adding/subtracting we will get the number .