
What will be the value of electric field at the Centre of the electric dipole:
A. Zero
B. Equal to the electric field due to one charge at the centre.
C. Twice the electric field due to one charge at the centre.
D. Half the value of the electric field due to one charge at the centre.
Answer
487.8k+ views
Hint: Let us first know about the Electric field. A physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field). It can also refer to a system of charged particles' physical field. Electric fields are created by electric charges or magnetic fields that change over time. The electromagnetic force, one of nature's four fundamental forces (or interactions), manifests itself in both electric and magnetic fields.
Complete step by step answer:
Let us know about the Dipole Moment. The dipole moment, a vector quantity, can be used to characterize dipoles, whether electric or magnetic. The electric dipole moment, in the case of a simple electric dipole, points from the negative charge to the positive charge and has a magnitude equal to the strength of each charge multiplied by the distance between the charges.
Using the equation, we can calculate the electric field created by a point charge.
$E = \dfrac{{kQ}}{{{a^2}}}$
${E^1} = \dfrac{{kQ}}{{{a^2}}} + \dfrac{{kQ}}{{{a^2}}} \\
\Rightarrow {E^1} = 2\dfrac{{kQ}}{{{a^2}}}$
$\therefore {E^1} = 2E$
So, option C is correct.
Note: Let us know more about electrical dipoles. In every electrical system, an electric dipole is used to separate the positive and negative charges. A pair of electric charges of equal magnitude but opposite sign separated by a typically small distance is a simple example of this system.
Complete step by step answer:
Let us know about the Dipole Moment. The dipole moment, a vector quantity, can be used to characterize dipoles, whether electric or magnetic. The electric dipole moment, in the case of a simple electric dipole, points from the negative charge to the positive charge and has a magnitude equal to the strength of each charge multiplied by the distance between the charges.
Using the equation, we can calculate the electric field created by a point charge.
$E = \dfrac{{kQ}}{{{a^2}}}$
${E^1} = \dfrac{{kQ}}{{{a^2}}} + \dfrac{{kQ}}{{{a^2}}} \\
\Rightarrow {E^1} = 2\dfrac{{kQ}}{{{a^2}}}$
$\therefore {E^1} = 2E$
So, option C is correct.
Note: Let us know more about electrical dipoles. In every electrical system, an electric dipole is used to separate the positive and negative charges. A pair of electric charges of equal magnitude but opposite sign separated by a typically small distance is a simple example of this system.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

