Answer
Verified
476.7k+ views
Hint: The refractive index of a medium is a measure of the speed of light in the medium. In a medium with a higher refractive index (optically denser), light travels slower than that in a medium of lower refractive index (optically rarer). It can also be written as the ratio of the speed of light in vacuum (or air) to the speed of light in that medium.
Formula used: The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Complete step by step answer:
We will solve this problem by using the formula for the refractive index of a medium and plugging in the information given in the question. Hence, let us proceed to do that.
The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$ -(1)
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Now, let the speed of light in diamond be $v=121000km.{{s}^{-1}}=121000\times {{10}^{3}}m.{{s}^{-1}}=1.21\times {{10}^{8}}m.{{s}^{-1}}$ $\left( \because 1km.{{s}^{-1}}={{10}^{3}}m.{{s}^{-1}} \right)$
Let the refractive index of diamond be $n$.
Putting this information in (1), we get,
$n=\dfrac{3\times {{10}^{8}}}{1.21\times {{10}^{8}}}=\dfrac{3}{1.21}\approx 2.47$
Hence, the refractive index of diamond is $2.47$.
Therefore, the correct option is B) $2.47$.
Note: Students sometimes get confused in the ratio for the formula for the refractive index of a medium. A good way to remember is that theoretically nothing and travel faster than the speed of light and the refractive index of a medium cannot be greater than one in general. Hence, the speed of light in the ratio must be in the numerator so that the ratio (or the refractive index of the medium) comes out to be greater than one.
Formula used: The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Complete step by step answer:
We will solve this problem by using the formula for the refractive index of a medium and plugging in the information given in the question. Hence, let us proceed to do that.
The refractive index $n$ of a medium in which the speed of light is $v$ is given by
$n=\dfrac{c}{v}$ -(1)
where $c=3\times {{10}^{8}}m/s$ is the speed of light in vacuum (or air).
Now, let the speed of light in diamond be $v=121000km.{{s}^{-1}}=121000\times {{10}^{3}}m.{{s}^{-1}}=1.21\times {{10}^{8}}m.{{s}^{-1}}$ $\left( \because 1km.{{s}^{-1}}={{10}^{3}}m.{{s}^{-1}} \right)$
Let the refractive index of diamond be $n$.
Putting this information in (1), we get,
$n=\dfrac{3\times {{10}^{8}}}{1.21\times {{10}^{8}}}=\dfrac{3}{1.21}\approx 2.47$
Hence, the refractive index of diamond is $2.47$.
Therefore, the correct option is B) $2.47$.
Note: Students sometimes get confused in the ratio for the formula for the refractive index of a medium. A good way to remember is that theoretically nothing and travel faster than the speed of light and the refractive index of a medium cannot be greater than one in general. Hence, the speed of light in the ratio must be in the numerator so that the ratio (or the refractive index of the medium) comes out to be greater than one.
Recently Updated Pages
Fill in the blanks with suitable prepositions Break class 10 english CBSE
Fill in the blanks with suitable articles Tribune is class 10 english CBSE
Rearrange the following words and phrases to form a class 10 english CBSE
Select the opposite of the given word Permit aGive class 10 english CBSE
Fill in the blank with the most appropriate option class 10 english CBSE
Some places have oneline notices Which option is a class 10 english CBSE
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
How do you graph the function fx 4x class 9 maths CBSE
Which are the Top 10 Largest Countries of the World?
What is the definite integral of zero a constant b class 12 maths CBSE
The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
Define the term system surroundings open system closed class 11 chemistry CBSE
Full Form of IASDMIPSIFSIRSPOLICE class 7 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE