Answer
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Hint: Use Poiseuille's equation. By Newton’s law of viscous flow, the viscous force is directly proportional to the surface area and change in its velocity. The flow of liquid is related to the factors like viscosity of the fluid , the pressure, length and the diameter of the tube. Hence by substituting the values in poiseuille's we will get the solution.
Formula used:
According to Poiseulli’s equation,
$Q=\dfrac{\pi (\vartriangle \operatorname{P}){{r}^{4}}}{8\eta L}$
where, Q is the rate of flow
P is the pressure
r is the inner radius of the tube
$\eta _{{}}^{{}}$ is the viscosity of the liquid
L is the length of the tube
Complete step by step solution:
According to Poiseulli’s equation,
$Q=\dfrac{\pi (\vartriangle \operatorname{P}){{r}^{4}}}{8\eta L}$
According to Ohm’s law,
V=IR …………..(1)
Which is similar to the poiseuille's equation.
That is, here the pressure difference is similar to potential difference, current is equal to the rate of flow of liquid and the constants are equal to resistance.
Thus rearranging the equation for pressure difference we get,
$\vartriangle P=Q\left[ \dfrac{8\eta L}{\pi {{r}^{4}}} \right]$ …………….(2)
Comparing equation (1) and (2),
Resistance,$R=\dfrac{8\eta L}{\pi {{r}^{4}}}$
Here, resistance is directly proportional to its length and inversely proportional to its radius.
New Resistance for the narrow tube,
$R'=\dfrac{8\eta L}{\pi {{\left( \dfrac{r}{3} \right)}^{4}}}$
$\begin{align}
& R'=\left( \dfrac{8\eta L}{\pi {{r}^{4}}} \right)\times {{3}^{4}} \\
& \\
\end{align}$
$\therefore R'=81R$
Thus option (D) is correct.
Note:
For deriving the formula for volume of a liquid flowing through a tube Poiseulli adopted some assumptions. That is, the flow of liquid in the tube is steady, streamline and parallel to the axis of the tube. There is no radial flow. The pressure over any cross section at right angles to the axis of the tube is constant. The velocity of the liquid layer in contact with the side of the tube is zero and increases in a regular manner as the axis of the tube is approached. The limitations of poiseuille's formula was it holds only for streamline flow of liquid. If the layers of the liquid in contact with the walls of the tube are not at rest and thus having relative slipping. This formula is true for fluid velocities, involving negligible amounts of kinetic energy.
Formula used:
According to Poiseulli’s equation,
$Q=\dfrac{\pi (\vartriangle \operatorname{P}){{r}^{4}}}{8\eta L}$
where, Q is the rate of flow
P is the pressure
r is the inner radius of the tube
$\eta _{{}}^{{}}$ is the viscosity of the liquid
L is the length of the tube
Complete step by step solution:
According to Poiseulli’s equation,
$Q=\dfrac{\pi (\vartriangle \operatorname{P}){{r}^{4}}}{8\eta L}$
According to Ohm’s law,
V=IR …………..(1)
Which is similar to the poiseuille's equation.
That is, here the pressure difference is similar to potential difference, current is equal to the rate of flow of liquid and the constants are equal to resistance.
Thus rearranging the equation for pressure difference we get,
$\vartriangle P=Q\left[ \dfrac{8\eta L}{\pi {{r}^{4}}} \right]$ …………….(2)
Comparing equation (1) and (2),
Resistance,$R=\dfrac{8\eta L}{\pi {{r}^{4}}}$
Here, resistance is directly proportional to its length and inversely proportional to its radius.
New Resistance for the narrow tube,
$R'=\dfrac{8\eta L}{\pi {{\left( \dfrac{r}{3} \right)}^{4}}}$
$\begin{align}
& R'=\left( \dfrac{8\eta L}{\pi {{r}^{4}}} \right)\times {{3}^{4}} \\
& \\
\end{align}$
$\therefore R'=81R$
Thus option (D) is correct.
Note:
For deriving the formula for volume of a liquid flowing through a tube Poiseulli adopted some assumptions. That is, the flow of liquid in the tube is steady, streamline and parallel to the axis of the tube. There is no radial flow. The pressure over any cross section at right angles to the axis of the tube is constant. The velocity of the liquid layer in contact with the side of the tube is zero and increases in a regular manner as the axis of the tube is approached. The limitations of poiseuille's formula was it holds only for streamline flow of liquid. If the layers of the liquid in contact with the walls of the tube are not at rest and thus having relative slipping. This formula is true for fluid velocities, involving negligible amounts of kinetic energy.
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